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Finger
7 days ago
7

. Statements: (1) The major force responsible for protein secondary structure is hydrogen bonding. (2) Amino acids found in prot

eins are almost always L-isomers. (3) Conjugated proteins always contain one or more prosthetic groups. a. All three statements are true. b. Two of the three statements are true. c. Only one of the statements is true. d. None of the statements are true.
Biology
2 answers:
11111nata11111 [2.5K]7 days ago
7 0

Answer:

a. All three claims are accurate.

Explanation:

The principal force that drives protein secondary structure arises from hydrogen bonding. The secondary structure is characterized by HYDROGEN BONDS that form between the amino group's hydrogen and the carboxyl group's oxygen atoms in the peptide backbone.

Proteins are composed predominantly of L-isomers of amino acids. All naturally occurring amino acids exist in their L-isomer forms.

Conjugated proteins are always associated with one or more prosthetic groups. Most proteins consist solely of amino acids and lack additional chemical groups, classified as simple proteins.

Some proteins can undergo hydrolysis, producing additional chemical components alongside amino acids; these are considered conjugated proteins. The non-amino segment of a conjugated protein is referred to as its prosthetic group, and in the absence of this group, the protein reverts to a simple form. Many prosthetic groups derive from vitamins.

garik1379 [2K]7 days ago
3 0

Answer:

a. All three claims are correct.

Explanation:

1. Hydrogen bonding serves as a major stabilizing element for protein structures, whether secondary or tertiary. It links a series of polypeptide chains through hydrophobic interactions.

2. Predominantly, amino acids within proteins appear as L (Laevorotatory)-isomers, forming the foundation of proteins. These L-isomers are critical for the biological functionality of tissues and cells.

3. A conjugated protein includes a non-amino acid component known as prosthetic groups. These components often come from vitamins that are necessary for the proper functioning of certain proteins.

Hence, it is true that all three claims hold.

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23 days ago
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Imagine that two unlinked autosomal genes with simple dominance code in goats for size, where T is tall and t is short, and for
enyata [2506]

Answer:

(A) 0.0625

(B) 25%

Explanation:

A

With the following:

T indicates tall

t indicates short

R indicates red

r indicates tan.

When a short tan male goat mates with a tall red female goat of an unknown genotype;

Let's analyze separately;

A short tan male goat = ttrr

The female goat’s genotype is not specified but it is known to be tall and red

∴ We determine that she must be T_ R_;

the potential genotype probability of the female for each allele could be:

- T

T

or Tt- RR

or R

r

Nonetheless, from earlier discussion;

the chance that the female is Tt = \frac{1}{2}

the probability of the female being Rr = \frac{1}{2}

the probability of passing on the recessive allele 't' to offspring = \frac{1}{2}

the probability of passing on the recessive allele 'r' to offspring = \frac{1}{2}

∴ the likelihood that the pairing would yield short, tan offspring (ttrr) stands at;

= (\frac{1}{2})^{4}

= (\frac{1}{16})

= 0.0625

(B)

In pea plants, one is homozygous recessive for both traits, leading to the cross of Yy Rr × yy rr. Determine the green and round offspring percentage.

For Color, let:

Y = Yellow

y = Green

For shape, let;

R = Round

r = wrinkled

If a cross occurs between Yy Rr × yy rr. (yellow round and green wrinkled)

the ratio of green and round offspring will be;

If Yy Rr self-crosses; various traits (YR, Yr, yR, yr)

yy rr will produce (yr, yr)

                   YR                    Yr                    yR                    yr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

                   Yellow              Yellow            Green              Green

                   Round               Wrinkled        Round              Wrinkled

                   Thus, the percentage of green and round offspring based on the above is:

=

%

\frac{2}{8}*100%=

%

\frac{1}{4}*100=

25%

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How do hair cells utilize these molecules for energy release allowing her to run?

Once glucose and oxygen enter the bloodstream, they are absorbed into cells, directed to mitochondria which convert them into energy in the form of ATP. Mitochondria are aptly referred to as the cell's powerhouse. Within each cell, energy release occurs in a sequence comprising glycolysis, the Krebs cycle, and oxidative phosphorylation. In this process, glucose reacts with oxygen, ultimately creating 36 ATP molecules per reaction run, sufficient to meet high energy demands. During exercise, both oxygen and glucose are supplied more rapidly due to the accelerated activity of the lungs and heart.

PS: Anaerobic respiration is not able to meet higher energy demands as it yields only 2 ATP per reaction.

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