Result: -50.005 kJ
Details:
Provided Data
mass of the system = 10 kg
work done = 0.147 kJ/kg
Elevation change 
initial speed 
Final Speed 
Specific internal Energy 
according to the first Law of thermodynamics
where KE represents kinetic energy
PE indicates potential energy
U denotes internal Energy
Q = 1.47 + 3.375 - 4.850 - 50
Q = -50.005 kJ
Answer:
She exerts a force of 40 N.
Explanation:
The fact that the ring remains stationary indicates that the forces are in equilibrium.
Let’s denote Jo's force as x.
The equation to consider is
140 = x + 100
x = 40
Answer
Given data:
height of the dam = 15 m
effective area for water flow = 2.3 x 10⁻³ m²
Applying the principle of energy conservation:
v = 17.15 m/s
water discharge
Q = A V
Q = 2.3 x 10⁻³ x 17.15
Q = 0.039 m³/s
In terms of light energy, a higher frequency corresponds to increased energy within the light.
We establish that frequency is essentially the inverse of wavelength:
frequency = 1 / wavelength
Calculating frequencies:
f UVA = 1/320 to 1/400
f UVA = 0.0031 to 0.0025
f UVB = 1/290 to 1/320
f UVB = 0.0034 to 0.0031
Since UVB occupies a higher frequency range, it consequently possesses greater energy than UVA.
