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andriy
9 days ago
5

a partially inflated weather balloon has a volume of 1.56 * 10^3 L and a pressure of 98.9 lPa. What is the volume of the balloon

when the ballon is released to a height where the pressure is 44.1 kPa
Physics
1 answer:
serg [3.4K]9 days ago
7 0
To find the solution, we start by listing down all initial data first, followed by what is sought and then the conclusion.

Given:

V1= 1.56x10^3 L = 1560 L                P2 = 44.1 kPa
P1 = 98.9 kPa

Required:  V2

Solution:

Assuming the gas behaves ideally. According to Boyle's Law, at a specific temperature, the pressure and volume product of a gas remains constant. It can be expressed as

PV = k

For this problem, we apply it as
 
P1*V1 = P2*V2
(98.9 kPa)*(1560 L) = (44.1 kPa)*V2
V2 = 3498.5 L

ANSWER: V2 = 3498.5 L
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The right answer is (a).

Solar panels create electric current through the photoelectric effect, which describes how photons strike certain material surfaces, resulting in the release of electrons when light with the correct frequency hits them. A photon will interact with an electron on the panel, causing it to be ejected from the panel's surface.

As the illumination on the panel becomes brighter, the intensity of the light rises, indicating an increase in the number of photons. Each photon has the potential to liberate an electron; thus, as the number of incoming photons rises, so does the quantity of freed electrons. Given that the photoelectric current reflects the rate at which these electrons flow, an increase in light intensity leads to a corresponding rise in the photoelectric current.

If the frequency of the light is increased without a change in brightness, the photoelectric current remains the same because the total number of photons does not increase. Yet, the electrons that are ejected do escape with higher kinetic energy. However, since the total number of electrons liberated stays unchanged, the current remains constant regardless of the electrons' increased energy. Thus, option b is incorrect.

Increasing the wavelength of the light means the energy of the photons decreases. This would cause the emitted electrons to have lower energy. However, if the brightness is consistent, the number of electrons remains the same, and as a result, there would be no change in the photoelectric current. Therefore, choice (c) is also incorrect.

The correct answer is (a). To generate the needed current, the brightness of the incident light must be increased.

8 0
1 month ago
Read 2 more answers
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 cans, 0.355 - l each,
Keith_Richards [3138]
Flow rate calculations yield 220 cans, each with a volume of 0.355 l, leading to 78.1 l/min or 1.3 l/s or 0.0013 m³/s.

At Point 2:
A2 = 8 cm² = 0.0008 m²
V2 = Flow rate/A2 = 0.0013/0.0008 = 1.625 m/s
P1 = 152 kPa = 152000 Pa

At Point 1:
A1 = 2 cm² = 0.0002 m²
V1 = Flow rate/A1 = 0.0013/0.0002 = 6.5 m/s
P1 =?
Height = 1.35 m

Using Bernoulli’s principle;
P2 + 1/2 * V2² / density = P1 + 1/2 * V1² / density + density * gravitational acceleration * height
=> 152000 + 0.5 * (1.625)² * 1000 = P1 + 0.5 * (6.5)² * 1000 + (1000 * 9.81 * 1.35)
=> 153320.31 = P1 + 34368.5
=> P1 = 1533210.31 - 34368.5 = 118951.81 Pa = 118.95 kPa
3 0
1 month ago
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A 55-kg pilot flies a jet trainer in a half vertical loop of 1200-m radius so that the speed of the trainer decreases at a const
Keith_Richards [3138]

a) -1.54 m/s^2

b) 803.4 N

Explanation:

a) At point C (top of the loop), the pilot experiences weightlessness, leading to the normal force from the seat being zero:

N = 0

Consequently, the force balance equation at position C becomes:

mg=m\frac{v^2}{r}where the left term signifies the pilot's weight and the right term represents the centripetal force, with:

= acceleration due to gravity

= jet's velocity at the top g=9.8 m/s^2

= loop radius

vBy solving for v,

r=1200 m

Thus, this is the jet's speed at C.

The speed at position A (bottom) can be derived fromv_C=\sqrt{gr}=\sqrt{(9.8)(1200)}=108.4 m/s

The distance traveled by the jet corresponds to half the circumference of the circle with radius r, therefore

v_A=550 km/h =152.8 m/s

Given the plane's deceleration is consistent, we can obtain it using the following equation:

s=\pi r=\pi(1200)=3770 m

b) The pilot experiences a force equal to the normal force from the seat. At point B (half-way through the loop), we find:

v_C^2-v_A^2=2as\\a=\frac{v_C^2-v_A^2}{2s}=\frac{108.4^2-152.8^2}{2(3770)}=-1.54 m/s^2- The normal force from the seat, N, directed towards the center of the loop

- As there are no further forces acting toward the central axis, N must equal the centripetal force:

(1)

where

represents the speed at position B.

To deduce the velocity at B, we note that the distance covered by the jet between positions A and B is a quarter of a circle:

With knowledge of the deceleration, we can implement the equation of motion to find the velocity at the midway point B:N=m\frac{v_B^2}{r}

v_B

Thus, we then apply eq.(1) to determine the normal force acting on the pilot at B:

s=\frac{\pi r}{2}=\frac{\pi(1200)}{2}=1885 m

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20 days ago
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serg [3462]
Utiliza Scoratic, funciona con cualquier tema.
5 0
17 days ago
Approximately 1.000 g each of four gasses H2, Ne, Ar, and Kr are placed in a sealed container all under1.5 atm of pressure. Assu
serg [3462]

Answer:

The partial pressure of H2 is 0.375 atm.

The partial pressure of Ne also stands at 0.375 atm.

Explanation:

Mass of H2 = 1 g

Mass of Ne = 1 g

Mass of Ar = 1 g

Mass of Kr = 1 g

Overall mass of the gas mixture totals 4 g.

Pressure in the sealed container is 1.5 atm.

Calculating the partial pressure for H2 yields: (mass of H2/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm.

Calculating the partial pressure for Ne similarly gives: (mass of Ne/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm.

7 0
1 month ago
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