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densk
7 days ago
8

The total floor area of a building, including below-grade space but excluding unenclosed areas, measured from the exterior of th

e walls" is the definition of _______________area.
Engineering
1 answer:
choli [298]7 days ago
6 0

Response:

Gross building area

Clarification:

Gross building area refers to the complete area of a building encompassing all floors. This measurement is expressed in square feet and also includes basements, penthouses, and mezzanines. It is determined by assessing the external dimensions of the structure. Storage areas, laundries, and staircases are also included in the gross building area.

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Daniel [329]
By securing stakeholder needs throughout the project planning stage via thorough process documentation that is revised after each work cycle.
7 0
1 month ago
Read 2 more answers
Helium gas is compressed from 90 kPa and 30oC to 450 kPa in a reversible, adiabatic process. Determine the final temperature and
choli [298]

Answer:

T2 ( final temperature ) = 576.9 K

a) 853.4 kJ/kg

b) 1422.3 kJ / kg

Explanation:

given data:

pressure ( P1 ) = 90 kPa

Temperature ( T1 ) = 30°c + 273 = 303 k

P2 = 450 kPa

To determine final temperature in an Isentropic process

T2 = T1 (\frac{p2}{p1} )^{(k-1)/k} ----------- ( 1 )

T2 = 303 ( \frac{450}{90})^{(1.667- 1)/1.667} = 576.9K

The work performed in a piston-cylinder device is calculated using the subsequent formula

w_{in} = c_{v} ( T2 - T1 )    ------- ( 2 )

where: cv = 3.1156 kJ/kg.k for helium gas

             T2 = 576.9K,    T1 = 303 K

substituting values into equation 2

w_{in} = 853.4 kJ/kg

the work done in a steady flow compressor is determined using this

w_{in} = c_{p} ( T2 - T1 )

where: cp ( constant pressure of helium gas ) = 5.1926 kJ/kg.K

             T2 = 576.9 k, T1 = 303 K

plugging values back into equation 3

w_{in} = 1422.3 kJ / kg

4 0
24 days ago
6.15. In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20
Viktor [391]

Explanation:

At a temperature of 33^{\circ} C and relative humidity of 86%, the humidity ratio stands at 0.0223 with a specific volume of 14.289.

At a temperature of 33^{\circ} C and relative humidity of 40%, the humidity ratio is 0.0066 while the specific volume is 13.535.

To determine the mass of air, the following formula can be used:

\begin{aligned}m _{1} &=\frac{ v }{ v }(1- w ) \\&=\frac{1 \times 10^{5}}{13.535}(1-0.0066) \\&=7339.49 lb / min \\v _{ a } &=\frac{ m _{1} v }{(1- w )} \\v _{ a } &=\frac{7339.49 \times 14.289}{(1-0.0223)} \\v _{ a } &=107266.0 ft ^{3} / min\end{aligned}

Now, we will calculate the volume

\begin{aligned}m _{ w } &=\frac{ v _{ a }}{ v _{ a }} w _{ a }-\frac{ v _{ i }}{ v _{ i }} w _{ i } \\&=\frac{107266.0}{14.289} \times 0.0223-\frac{100000}{13.535} \times 0.0066 \\&=118.64 lb / min\end{aligned}

The duration required to fill the cistern can be determined with the equation:

Time \(=\frac{\text { cistern volume }}{\text { removal water perminute volume }}\)

By substituting the values into the preceding formula, we find:

\(\frac{\left(15 \times 10^{3} L\right) \times\left(0.0353147 ft ^{3} / L \right)}{(118.641 b / min ) \times\left(\frac{1}{62.41 lb / ft ^{3}}\right)}\)\\\(=279.09\) minutes\\\(=4.65\) hours.

Thus, the hours necessary to fill the cistern amount to 4.65 hours.

3 0
1 month ago
. A storm sewer is carrying snow melt containing 1.200 g/L of sodium chloride into a small stream. The stream has a naturally oc
Kisachek [356]

Answer:

Explanation:

In a steady-state condition, the total volume exiting matches the total volume entering, and

the total amount of salt entering equals the total amount of salt exiting.

The volume entering each minute is = 2000 + 2 x 10³ x 60

= 122000 L.

The total salt entering per minute = 1200 x 2000 + 20 x 2 x 10³ x 60

= 2400000 + 2400000 mg

= 4800000 mg.

The volume of water exiting each minute = 122000 L.

The total salt exiting each minute = 4800000 mg.

The concentration of salt in the exiting water = 4800000 / 122000

= 39.344 mg / L.

3 0
1 month ago
In a heat-treating process, a 1-kg metal part, initially at 1075 K, is quenched in a closed tank containing 100 kg of water, ini
mote1985 [299]

Answer:

provided below

Explanation:

8 0
29 days ago
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