All categories

14 days ago

An electric field is expressed in rectangular coordinates by E = 6x2ax + 6y ay +4az V/m.Find:a) VMN if point M and N are specifi

ed by M(2,6,1) and N(-3, -3, 2).b) VM if V = 0 at Q(4, -2, -35)c) VN if V = 2 at P(1,2,4).Please show all steps

You might be interested in

At what forward voltage does a diode conduct a current equal to 10,000 Is ? In terms of Is , what current flows in the same diod

pantera1 [306]

Answer:a) The forward voltage is 0.23 V

b) The current that flows

$I_{d} = (1.45*10^{12}I_{s})A$

Explanation:

The forward voltage refers to the minimum voltage required for a diode to start conducting. The formula used is given by:

a) At which forward voltage does a diode allow a current equal to 10,000 Is? In terms of Is

$I_{d} = I_{s}(e^{\frac{v_{f} }{0.025} }-1)$

Where:

Id denotes the diode current = 10000Is,

Vd stands for the forward voltage at which conduction begins,

Is indicates the saturation current.

$I_{d} = I_{s}(e^{\frac{v_{f} }{0.025} }-1)$

$10000I_{s} = I_{s}(e^{\frac{v_{f} }{0.025} }-1)$

By dividing through by Is,

$10000 = (e^{\frac{v_{f} }{0.025} }-1)$

$10000 +1= e^{\frac{v_{f} }{0.025} }$

$10001= e^{\frac{v_{f} }{0.025} }$

Taking the natural log of both sides,

$ln(10001)= {\frac{v_{f} }{0.025} }$

$9.21= {\frac{v_{f} }{0.025} }$

Multiplying through by 0.025 yields

= 0.23 V

This indicates the forward voltage at which the diode conducts a current equal to 10,000 Is is 0.23 V

b) What current flows in the same diode when the forward voltage is 0.7 V?

$I_{d} = I_{s}(e^{\frac{v_{f} }{0.025} }-1)$

$I_{d} = I_{s}(e^{\frac{0.7}{0.025} }-1)$

$I_{d} = I_{s}(1.45*10^{12} -1)$

$I_{d} = (1.45*10^{12}I_{s})A$

6 0

1 month ago

5 kg of steam contained within a piston-cylinder assembly undergoes an expansion from state 1, where the specific internal energ

Daniel [329]

Answer:

Energy Transfer = 350 kJ

Explanation:

The net work can be derived from the energy balance equation. Thus, we have:

∆KE + ∆PE + ∆U = Q − W

Where

∆KE = ∆PE = 0 (Since there’s no notable change in either kinetic or potential energy of the steam)

Net work comprises the work done by the paddlewheel, Wpw,

and the work on the piston, Wpiston:

W = Wpw + Wpiston

From the data provided, Wpw = −18.5 kJ,

Summarizing results:

Wpw + Wpiston = Q − ∆U

Wpiston = Q − ∆U − Wpw = Q − m (u2 − u1) − Wpw

Where Q = 80 kJ, m = 5 kg, u2 = 2659.6 kJ/kg, and u1 = 2709.9 kJ/kg

= 80 kJ − 5 kg (2659.6 − 2709.9) kJ/kg − (−18.5 kJ)

= 350 kJ

4 0

2 months ago

The most flexible and mobile method of supplying our need for mechanical energy has been the internal-__________ engine. (10 let

Daniel [329]

Answer:

Combustion

Explanation:

This relates to an internal-combustion engine.

4 0

2 months ago

Read 2 more answers

In which of the following branches of engineering is the practice not restricted?

iogann1982 [368]

a) civil engineering.

6 0

1 month ago

Read 2 more answers