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laiz
2 months ago
8

The Wright Flyer was the first successful powered aircraft. A model was made to display in a museum with the length of 35 cm and

a wingspan of about 66.9 cm. The length of the actual plane was 21 ft 1 in., and the height was 2.74 m. Compare the length, height, and wingspan of the model to the actual plane and explain why any errors may occur. (Round any calculations to the nearest whole number.)
Mathematics
1 answer:
Zina [12.3K]2 months ago
8 0

<span>To relate the displayed model of the Wright Flyer in the museum to the actual airplane, we must determine the relationship of the respective measurements. In this scenario, both the exhibition and real plane have a defined length. The ratio is calculated as follows,</span>

<span>
    ratio = length of the model / length of the actual plane

Model length = 35 cm</span>

<span>
We will convert the model length to ft.</span>

<span>
model length = (35 cm)(1 in/2.54 cm)(1 ft/12 in)
model length = 1.148 ft

</span>

<span>
</span>

<span>Returning to the ratio calculation,[symbol]ratio = (1.148 ft)/21 ft
ratio = 0.055

Therefore, the model's dimensions are approximately 0.055 of the actual measurements.

Errors could arise due to the precision of significant figures during the rounding process in calculations.</span>

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3 months ago
The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
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Response:

a

    f'(t) is negative

b

 The unit is degC/min

c

At 35 minutes since the coffee was placed on the counter, the temperature is 68, and it will drop by approximately 0.75 in the next 30 seconds.

Detailed explanation:

According to the question, we are informed that

   The temperature of a cup of coffee on a counter is represented by the equation

         H= f(t)

where t indicates the time in minutes since the coffee was set on the counter.

In general, f(t)' denotes the derivative of f(t), indicating the change in temperature over time for the coffee

As the coffee rests on the counter, its temperature tends to decrease after a few minutes; thus, f(t)' is negative.

The temperature is measured in degrees Celsius while time is expressed in minutes.

Therefore, the change in temperature with respect to time, f(35)', will be given in degrees Celsius per minute (i.e., degC/min).

The question states that

        |f(35)'| = 1.5

which means the rate of temperature change after 35 minutes is 1.5.

And

         |f(35)| = 68

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Subsequently, after another t= 30 seconds = \frac{30}{60}= 0.5 \ minutes the rate at which the coffee's temperature changes is

          R = |f(35)'| * t

=>        R = 1.5 * 0.5

=>        R = 0.75    

Thus

At 35 minutes since the coffee was placed on the counter, its temperature is 68 and will drop by roughly 0.75 in the next 30 seconds.

     

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