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natta225
9 days ago
9

A scientist works for a drug company and runs experiments on their product with results that favor the company's product. This i

s an example of_________.
(A.) conflict of interest and confirmation bias.


(B.) getting the inside scoop about a product, buying company stock, and making a lot of money.


(C.) sound and reliable science practices.


(D.) all the above.
Chemistry
1 answer:
lorasvet [2.7K]9 days ago
8 0
I believe this illustrates biased information since it stems from his own team's research.
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On occasion, it has been found that the oxidation of borneol doesn't go to completion (possibly because of poor stirring or insu
VMariaS [2998]

Response:

Examine the explanation

Explanation:

In this scenario, Nitrogen (N) experiences oxidation while Chlorine (Cl) undergoes reduction.

In response to your inquiry:

N is oxidized from an oxidation state of -3 to -1.

Cl is reduced from an oxidation state of +1 to -1.

At this point,

Borneol will likely exhibit a lower Rf due to its boiling point.

3 0
16 days ago
A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
KiRa [2933]

Answer:

There are 5.5668 moles of water for every mole of CuSO₄.

Explanation:

The mass of anhydrous CuSO₄ is:

23.403g - 22.652g = 0.751g.

mass of crucible + lid + CuSO₄ - mass of crucible + lid

Given that the molar mass of CuSO₄ is 159.609g/mol, we calculate the moles:

0.751g ×\frac{1mol}{159,609g} = 4.7052x10⁻³ moles CuSO₄

The mass of water in the initial sample is:

23.875g - 0.751g - 22.652g = 0.472g.

mass of crucible + lid + CuSO₄ hydrate - CuSO₄ - mass of crucible + lid

As the molar mass of H₂O is 18.02g/mol, we find the moles:

0.472g ×\frac{1mol}{18,02g} = 2.6193x10⁻² moles H₂O

The mole ratio of H₂O to CuSO₄ is:

2.6193x10⁻² moles H₂O / 4.7052x10⁻³ moles CuSO₄ = 5.5668

This indicates there are 5.5668 moles of water per mole of CuSO₄.

I hope this is helpful!

5 0
1 month ago
Given the connection between Aw and K (Aw=2k) could you use the ideal gas law and derive the Boltzmann constant. Water freezes a
lions [2927]

Answer:

Explanation:

The relationship between the new temperature scale and the absolute temperature scale is defined as follows

Aw = 2 K

for K = 273.15 (the freezing point of water on the absolute scale)

Aw = 2 x 273.15 = 546.3 K

Each division of the new scale is equivalent to half that of each division on the absolute scale

each division of the new scale is minimal.

The value of R = 8.314 J per mole per K

Here, per K corresponds to 2Aw

Hence, the value of R in the new scale = 8.314/2 J per mole per Aw

= 4.157 J per mole per Aw

k = R / N

= 4.157 / 6.02 x 10²³

= .69 x 10⁻²³

= 6.9 x 10⁻²⁴ J per molecule per Aw .

7 0
2 months ago
Read 2 more answers
C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti
Tems11 [2777]

Response:

Ethanol serves as a reducing agent.(C_2H_5OH)

The lowest integer coefficient for MnO_4^- in the balanced equation is 4

Clarification:

A redox reaction, or oxidation-reduction reaction, is defined as one in which oxidation and reduction processes occur simultaneously.

Oxidation is the process whereby a substance loses electrons, resulting in an increase in oxidation state. In contrast, reduction entails a substance gaining electrons, leading to a decrease in oxidation state.

Reducing agents enable other substances to undergo reduction while becoming oxidized themselves.

Conversely, oxidizing agents facilitate other substances' oxidation while being reduced in the process.

For the chemical reaction in question, the half-reaction would be:

Oxidation:

Reduction:

To balance the oxygen atoms on both sides

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

For oxidation:

For reduction:

C_2H_6O\rightarrow C_2H_4O_2

MnO_4^-\rightarrow Mn^{2+}Then balance the hydrogen atoms on both sides.

  • For oxidation:
For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2

Lastly, balance the charge.MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • For oxidation: For reduction:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

To balance the electrons, multiply the oxidation reaction by 5 and the reduction by 4 before combining both equations for a balanced redox reaction.

MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2OOxidation:

  • Reduction:
The finalized balanced chemical equation in acidic conditions will be:

C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In this redox process, ethanol acts as the reducing agent while the permanganate ion serves as the oxidizing agent.

4 0
12 days ago
The value of delta G at 141.0 degrees celsius for the formation of phosphorous trichloride from its constituent elements,
VMariaS [2998]
The appropriate answer is option E. Gibbs free energy can be expressed using the equation: ΔG = ΔH - TΔS, where ΔH denotes the change in enthalpy of the reaction, T is the reaction temperature, and ΔS signifies entropy change. For our calculations, we have ΔH = -720.5 kJ/mol which converts to -720500 J/mol (given that 1 kJ = 1000 J), ΔS = -263.7 J/K, and T = 141.0°C, which equals 414.15 K. Consequently, the Gibbs free energy for the specified reaction at 141.0°C is calculated as -611.3 kJ/mol.
6 0
25 days ago
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