Answer:
Explanation:
Assuming all calculations occur at standard pressure and a temperature of -1.72°C :
Where
is the number of moles of hydrogen
is the mass of hydrogen
is the density of hydrogen
<span>Some solutions demonstrate colligative properties, which rely on the quantity of solute in a solvent. To find the elevation in boiling point, we use the formula:
</span><span>ΔT(boiling point) =
(Kb)mi
where Kb represents a constant, m is the solution's molality, and i is the van't Hoff factor.
From the provided information, we can easily determine i as follows:
</span>ΔT(boiling point) = (Kb)mi
103.45 - 100 = (0.512)3.90i
i = 1.73 <-------van't Hoff factor
Answer:
(C) The average speed of molecules in ethane is the same as that of propanol.
Explanation:
In gas behavior, temperature is directly linked with speed. At a constant temperature, speed remains consistent. Also, we understand that ideal gases exhibit uniform behavior, irrespective of their type.
A triprotic acid is a type of Arrhenius acid that has the ability to donate three protons per molecule during dissociation in aqueous solutions. Thus, the chemical reaction, as outlined in the question, at the third equivalence point, can be expressed as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R denotes the counter ion of the triprotic acid. Consequently, the ratio of reacted acid to base at this point is 1:3.
The moles of NaOH are calculated as 0.106M*0.0352L = 0.003731 mole. Therefore, the amount of H3R is 0.003731mole/3=0.001244mole.
Subsequently, the molar mass of the acid can be determined: 0.307g/0.001244mole=247 g/mol.
At equilibrium, [R] = [Z] > [Q]. Explanation: In analyzing the equilibrium conditions, the provided reaction of X(g) + 2 Q(g) ⇄ R(g) + Z(g) establishes that at a temperature of 50ºC, the equilibrium constant Kc = 1.3 x 105. This indicates a scenario where the concentrations of the products greatly exceed those of the reactants.
