NiO is to be reduced to nickel metal in an industrial process by use of the reaction:NiO(s) + CO(g) <-----> Ni(s) + CO2(g)
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Answer:
1) This dilution plan will yield a 200μM solution.
2) This dilution plan will not yield a 200μM solution.
3) This dilution plan will not yield a 200μM solution.
4) This dilution plan will yield a 200μM solution.
5) This dilution plan will yield a 200μM solution.
Explanation:
Convert the initial molarity into molar form as shown.
Let's examine the following serial dilution processes.
1)
Dilute 5.00 mL of the stock solution to 500 mL. Then take 10.00 mL of this new solution and dilute it further to 250 mL.
Concentration of 500 mL solution:
10 mL of this solution is further diluted to 250 mL
Convert μM:
Thus, this dilution scheme will yield a 200μM solution.
2)
Dilute 5.00 mL of the stock solution to 100 mL. Then take 10.00 mL of this new solution and dilute to 1000 mL.
Concentration of 100 mL solution:
10 mL of this solution is further diluted to 1000 mL
Convert μM:
Thus, this dilution scheme will not yield a 200μM solution.
3)
Dilute 10.00 mL of the stock solution to 100 mL, followed by diluting 5 mL of that new solution to 100 mL.
Concentration of 100 mL solution:
5 mL of this solution is diluted to 1000 mL
Convert μM:
Thus, this dilution scheme will not yield a 200μM solution.
4)
Dilute 5 mL of the stock solution to 250 mL. Then take 10 mL of this new solution and further dilute it to 500 mL.
Concentration of 250 mL solution:
10 mL of this solution is further diluted to 500 mL
Convert μM:
Thus, this dilution scheme will yield a 200μM solution.
5)
Dilute 10 mL of the stock solution to 250 mL. Then take another 10 mL of this new solution and dilute it to 1000 mL.
Concentration of 250 mL solution:
10 mL of this solution is further diluted to 1000 mL
Convert μM:
Thus, this dilution scheme will yield a 200μM solution.