The function representing the cost per share, C, relative to the number of contributors, n, is C = 500 / n. For the contribution to be $20 each, Jane must gather 20 additional contributors, totaling 25. With just 5 currently, she needs 20 more to reach this goal.
In February, 423 daytime minutes were utilized. Let x represent the base plan charges and y denote the cost per daytime minute. In December, the equation is x + 510y = 92.25. In January, it is x + 397y = 77.56. When we eliminate eq(2) from eq(1), we find 0 + 113y = 14.69, leading to y being \frac{14.69}{113}, thus y = 0.13. Substituting (3) into (1) gives x + 510(0.13) = 92.25, further simplifying to x + 66.3 = 92.25, which results in x = 25.95. Hence, for February: base plan + (daytime minutes)(0.13) = 80.9, which simplifies to (daytime minutes)(0.13) = 54.95, yielding daytime minutes = 422.69.
Here are the steps to solve for the value of x in the equation: x/3 - 7 = 11. We start by moving 7 to the opposite side of the equation, changing its sign from negative to positive, resulting in x/3 = 11 + 7, or x/3 = 18. To isolate x, multiply both sides of the equation by 3, yielding x alone on one side. Thus, we find x = 54. If the equation were instead expressed as 3x - 7 = 11, the solution would give x = 6.
