Answer:
H = 109.14 cm
Explanation:
Given,
Assume that the total energy equals 1 unit.
Energy remaining after the first collision = 0.78 x 1 unit
Balance after the first impact = 0.78 units
Remaining energy after the second impact = 0.78 ^2 units
Balance after the second impact = 0.6084 units
Remaining energy after the third impact = 0.78 ^3 units
Balance after the third impact = 0.475 units
The height reached after the third collision is equivalent to the remaining energy.
Let H denote the height achieved after three bounces.
0.475 (m g h) = m g H
H = 0.475 x h
H = 0.475 x 2.3 m
H = 1.0914 m
H = 109.14 cm
In static equilibrium, all forces balance out. Therefore, to simplify, start by breaking down F1 into its horizontal and vertical components. Since no other forces act horizontally, F1's horizontal component is known to be 40N. This information can be used to determine the vertical component using the Pythagorean theorem. Once the components are established, simply add the vertical components to calculate the difference between the upward and downward forces.
We will utilize Wien's displacement law, given by the equation λ T = b, where λ represents the wavelength of emitted light from a heated object at maximum. By substituting the provided temperature and constant b into the equation, we find λ for various temperatures: at 500 K, λ = 5.796 μm or 5796 nm; at 1050 K, λ = 2760 nm; at 1800 K, λ = 1610 nm; and at 2500 K, λ = 1159.2 nm. The visible light spectrum starts at 740 nm, suggesting that at 2500 K, some visible red light may emerge as its calculated peak wavelength is within the visible range.
Answer:
1.5 × 10³⁶ light-years
Explanation:
A particular square area in interstellar space measures roughly 2.4 × 10⁷² (light-years)². To find the area of a square, the following formula is utilized:
A = l²
where,
A represents the area of the square
l denotes the length of one side of the square
Thus, l = √A = √2.4 × 10⁷² (light-years)² = 1.5 × 10³⁶ light-years
Answer:
The tension in the string when the speed increased is 134.53 N
Explanation:
Given;
Tension in the string, T = 120 N
initial speed of the transverse wave, v₁ = 170 m/s
final speed of the transverse wave, v₂ = 180 m/s
The wave speed is expressed as;

where;
μ represents mass per unit length

The new tension T₂ will be computed as;

Consequently, the tension in the string when the speed was increased is 134.53 N