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Vilka
18 days ago
15

Find the net electric force that the two charges would exert on an electron placed at point on the xx-axis at xx = 0.200 mm. Exp

ress your answer with the appropriate units. Enter positive value if the force is in the positive xx-direction and negative value if the force is in the negative xx-direction.

Physics
1 answer:
Keith_Richards [2.2K]18 days ago
6 0

Response:

Some details are lacking in the question; here’s the complete version: A -3.0 nC point charge is positioned at the origin, while a -5.0 nC point charge exists along the x-axis at x = 0.800 m. Determine the overall electric force that the two charges would have on an electron situated at 0.200 m along the x-axis.

Clarification:

Coulomb's law applies to solve this problem as illustrated in the accompanying file.

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According to a rule-of-thumb. every five seconds between a lightning flash and the following thunder gives the distance to the f
ValentinkaMS [2425]

Answer:

S_{s}=300 m/s

According to the guideline for kilometers, every three seconds between a lightning strike and the subsequent thunder indicates the distance to the flash in kilometers.

Explanation:

To calculate the speed of sound in meters per second, we need to utilize certain conversion factors. One mile corresponds to 5 seconds after witnessing the lightning. Furthermore, 1 mile comprises 5280 feet, and 1 foot is equivalent to 0.3048 meters. This information is sufficient to solve the issue. The conversion ratios can be set up like this:

\frac{1mi}{5s}*\frac{5280ft}{1mi}*\frac{0.3048m}{1ft}=321.87m/s

Observe how the ratios are organized such that the units cancel out during calculations. One ratio has miles in the numerator while the other has them in the denominator, leading to cancellation. The same applies to the feet.

The question requires us to provide the answer to one significant figure, resulting in the speed of sound rounding to 300m/s.

For the second part, we will again utilize conversions. This time we will set our ratios in reverse and realize that there are 1000 meters in 1 kilometer, leading us to:

\frac{5s}{1mi}*\frac{1mi}{5280ft}*\frac{1ft}{0.3048m}*\frac{1000m}{1km}=3.11s/km

This signifies that for every 3.11 seconds, the distance to the lightning strike is 1 kilometer. Since this is a fabric of general knowledge, we round to the nearest whole number for simplicity, establishing the guideline:

According to the rule for kilometers, every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

3 0
18 days ago
A 5-kg concrete block is lowered with a downward acceleration of 2.8 m/s2 by means of a rope. The force of the block on the Eart
Maru [2355]

The moment the body impacts the ground, two types of Forces are produced: the gravitational pull and the Normal Force. This aligns with Newton's third law, indicating that every action has an equal and opposite reaction. If the downward force of gravity is directed toward the earth, the reactionary force from the block acts upwards, equivalent to its weight:

F = mg

Where,

m = mass

g = gravitational acceleration

F = 5*9.8

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Consequently, the answer is E.

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17 days ago
To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of th
Softa [2029]

Answer:

H = 10.05 m

Explanation:

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therefore, the total duration of the upwards motion above the peak of the pole is provided as

\Delta t = 4.1 - 0.5 = 3.6 s

now we have

\Delta t = \frac{2v}{g}

3.6 = \frac{2v}{9.8}

v = 17.64 m/s

this indicates the speed at the flagpole's top

at this point we have

v_f - v_i = at

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the height of the flagpole is stated as

H = \frac{v_f + v_i}{2}t

H = \frac{22.5 + 17.64}{2} (0.5)

H = 10.05 m

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1 month ago
Mike recently purchased an optical telescope. Identify the part of the electromagnetic spectrum that is closest to the frequency
kicyunya [2264]
The electromagnetic spectrum spans from radio waves to gamma rays. The picture provided illustrates this entire spectrum. However, the optical telescope is limited to observing only the visible spectrum, which ranges from 400 nm to 700 nm. This segment reflects the colors of ROYGBIV, with red exhibiting the highest frequency and violet the lowest frequency.

8 0
21 day ago
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Sav [2226]

Answer:

I'm uncertain

Explanation:

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