Answer:
The air exiting from the hairdryer is moving at a speed of 10 m/s.
Explanation:
The thrust generated by the hairdryer enables it to maintain an elevation angled at 5° from vertical; thus, we derive from the force diagram
by substituting 
, 
into the equation and resolving for 
we find:
This thrust is linked to the speed of air ejection 
through the equation
where 
signifies the rate of air ejection, which is known to be
and since 
,
by inserting these values into equation (2), we obtain the value of as:
resulting in
which indicates the air velocity discharged from the hairdryer.
2*3.5 = 7m/s
You need to multiply the acceleration by the time (which must both be in seconds; if not, convert them to the same units).
The formula for range is:
Given values are:
where θ equals 14.1 degrees
Using the equation above,
The calculated range is 66.7 meters.
Therefore, the range is approximately 66.1 meters.
Answer:
The distance covered by the minutes hand is 39.60 cm.
Explanation:
Note: A clock has a circular shape, where the minutes hand acts as the radius, and its motion creates an arc.
Length of an arc is calculated as ∅/360(2πr)
L = ∅/360(2πr).................... Equation 1π
Here, L represents the arc’s length, ∅ is the angle made by the arc, and r is the arc’s radius.
Given: ∅ = 252°, r = 9 cm, π = 3.143.
Upon substituting these values into equation 1,
L = 252/360(2×3.143×9)
L = 0.7×2×3.143×9
L = 39.60 cm.
Thus, the distance traversed by the minutes hand is 39.60 cm.
