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Andru
21 day ago
12

When a downward force is applied at a point 0.60 m to the left of a fulcrum, equilibrium is obtained by placing a mass of 10–7 k

g at a point 0.40 m to the right of the fulcrum. What is the magnitude of the downward force
Physics
1 answer:
ValentinkaMS [3.4K]21 day ago
4 0

Answer:

force = 6.53× 10^{-7} N

Explanation:

Provided data

downward force = 0.60 m

mass m = 10^{-7} kg

distance h = 0.40 m

to determine

magnitude of the downward force

solution

we know here mg is apply 0.4 m away from support and

thus applied force is d = 0.6 m from support

therefore

by balancing torque we can compute force

as

force = mass × g × h / d

substituting the values

force = mass × g × h / d

force = ( 10^{-7} × 9.81 × 0.4 ) / 0.6

force = 6.53× 10^{-7} N

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Explanation:

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\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ

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Suppose that you measure the light of a star between 640 and 680 nm and you get a very strong peak around 650 nm. what can you s
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11 days ago
A block of mass m, initially held at rest on a frictionless ramp a vertical distance H above the floor, slides down the ramp and
kicyunya [3294]

Answer:

\displaystyle W=-m.g.H

Explanation:

Transformation of Energy

Also known as energy conversion, this refers to the process in which energy shifts from one type to another. In this context, three energy forms are involved. When the object is stationary at the ramp's peak, it possesses gravitational potential energy, calculated as

U=m.g.H

As the object descends the frictionless ramp, it converts all its potential energy into kinetic energy, represented as

\displaystyle K=\frac{m.v^2}{2}

Thus,

K=m.g.H

Ultimately, when the object encounters a rough surface, all energy converts to thermal energy. The work performed by the friction force corresponds to the alteration in kinetic energy, as all velocity is lost in this process:

\displaystyle W=\Delta E=K_f-K=0-K=-\frac{m.v^2}{2}

Given the kinetic energy equals the initial potential energy:

\boxed{\displaystyle W=-m.g.H}

The negative sign indicates that the work acted against the direction of movement, meaning the force and displacement are 180° apart.

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7 0
1 month ago
A car has a mass of 1600 kg. It is stuck in the snow and is being pulled out by a cable that applies a force of 7560 N due north
Ostrovityanka [3204]

Response:

The car's acceleration will be a=0.1375m/sec^2

Reasoning:

We are provided with a mass for the ball, m = 1600 kg

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Thus, the overall force acting on the car F_{net}=F-F_R=7560-7340=220N

According to Newton's second law, we understand that F=ma

Therefore 220=1600\times a

a=0.1375m/sec^2

7 0
1 month ago
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