Answer:
A rock weighing 50kg should be positioned at a distance of 0.5m from the pivot of the seesaw.
Explanation:
τchild=τrock
We will utilize the formula for torque:
(F)child(d)child)=(F)rock(d)rock)
The gravitational force acts equally on both objects.
(m)childg(d)child)=(m)rockg(d)rock)
We can eliminate gravity from both sides of the equation for simplification.
(m)child(d)child)=(m)rock(d)rock)
Now employing the given masses for the rock and child. The seesaw's total length is 2 meters, with the child sitting at one end, placing them 1 meter from the center of the seesaw.
(25kg)(1m)=(50kg)drock
Solve for the distance where the rock should be positioned in relation to the seesaw's center.
drock=25kg⋅m50kg
drock=0.5m
Response:
U = 12,205.5 J
Clarification:
To determine the internal energy of an ideal gas, use the following equation:
(1)
U: internal energy
R: ideal gas constant = 8.135 J(mol.K)
n: number of moles = 10 mol
T: the temperature of the gas = 100K
Substituting the parameter values into equation (1):

The overall internal energy for 10 moles of Oxygen at 100K is 12,205.5 J
Explanation:
The term 'collision' refers to the interaction between two objects. There are two distinct types of collisions: elastic and inelastic.
In this scenario, two identical carts are heading towards each other at the same speed, resulting in a collision. In an inelastic collision, the momentum is conserved before and after the incident, but kinetic energy is lost.
After the event, both objects combine and move together at a single velocity.
The graph representing a perfectly inelastic collision is attached, illustrating that both carts move together at the same speed afterward.
Response:
83.1946504051 m
Rationale:
u = Starting velocity = 
s = Distance traveled = 
= Incline = 

Friction coefficient



The calculated stopping distance is 83.1946504051 m
Answer:
x = 0.29 m
Explanation:
It is known that the total external force acting on the mass system equals ZERO,
so the center of mass of the entire system will stay stationary.
We find that

Since Ernie approaches Burt's position, we have:


therefore, we conclude that

