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Taya2010
9 days ago
15

Arm abcd is pinned at b and undergoes reciprocating motion such that θ=(0.3 sin 4t) rad, where t is measured in seconds and the

argument for the sine is in radiaus. determine the largest speed of point a during the motion and the magnitude of the acceleration of point d at this instant.
Physics
1 answer:
Ostrovityanka [3K]9 days ago
8 0
<span>θ=0.3sin(4t)
w=0.3cos(4t)(4)=1.2cos(4t)
a=-4.8sin(4t)

Knowing that the maximum of cos4t is always 1 (as seen in the cosine graph), similarly, sin4t will always equal 0

Thus, the maximum rate of w = 1.2 rad/s
 
vAmax=r*w=250*1.2=300 mm/s
(may vary if your graph/radius is derived from a different source)

adt=a*r=200*-4.8sin(4t)=0 (when sin(4t)=0)

adn=r*w^2=200*1.2^2=288

ad= the square root of adt^2 + adn^2 = 288 mm/s^2</span>
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