A 25kg child sits on one end of a 2m see saw. How far from the pivot point should a rock of 50kg be placed on the other side of

Details that are not provided: the problem figure is included.

We can address the exercise by applying Poiseuille's law. This law indicates that for a fluid flowing in a laminar manner within a confined pipe,

where:

represents the pressure difference across the two ends

denotes the viscosity of the fluid

L signifies the length of the pipe

indicates the volumetric flow rate, where is the cross-sectional area of the tube and refers to the fluid's velocity

r stands for the pipe's radius.

This law can be utilized for the needle, allowing us to compute the pressure difference between point P and the needle's end. In this scenario, we have:

is the dynamic viscosity of water at

L=4.0 cm=0.04 m

and r=1 mm=0.001 m

Substituting these values into the formula yields:

This pressure difference specifies the value between point P and the needle's termination. As the end of the needle is under atmospheric pressure, the gauge pressure at point P, relative to atmospheric pressure, is exactly 3200 Pa.

Answer:

Electric flux is calculated as

Explanation:

We start with the given parameters:

The electric field impacting the circular surface is

Our objective is to ascertain the electric flux passing through a circular region with a radius of 1.83 m situated in the xy-plane. The area vector is oriented in the z direction. The formula for electric flux is expressed as:

Applying properties of the dot product, we calculate the electric flux as:

Consequently, the electric flux for the circular area is . Thus, this represents the required answer.

A larger section of a forest is likely to support more diverse species compared to a smaller section of the same forest. Additionally, a half acre of rainforest is expected to exhibit more biodiversity than a full acre of desert. Biodiversity refers to the variety found within an ecosystem, which encompasses differences among living organisms based on their species and habitats. Generally, ecosystems with larger areas tend to have greater biodiversity; hence, a substantial forest area would likely harbor more biodiversity than a smaller area within it. Similarly, the previous example illustrates that a half acre of rainforest would likely have a higher level of biodiversity compared to one acre of a desert.

The question pertains to the change in frequency of a wave noted by an observer moving in relation to the source, indicating that the concept to invoke is "Doppler's effect."

The standard formula for the Doppler effect is:
-- (A)

Note that we don’t need to be concerned with the signs here, as all entities are moving toward each other. If something was moving away, a negative sign would apply, but that is not relevant to this scenario.

Where,
g = Speed of sound = 340m/s.
= Velocity of the observer relative to the medium =?.
= Velocity of the source in relation to the medium = 0 m/s.
=  Frequency emitted from the source = 400 Hz.
= Frequency recognized by the observer = 408 Hz.

Substituting the given values into equation (A) will yield:





Solving the above will result in,
= 6.8 m/s

The correct result = 6.8m/s

Answer:

option D.

Explanation:

The correct choice is option D.

For an object in equilibrium, the torque measured at any point will be zero.

An object is deemed to be in equilibrium when the net moment acting on it equals zero.

If the object experiences a net moment not equal to zero, it will rotate and will not remain stable.