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Art
11 days ago
15

The endpoints of JK are J(–25, 10) and K(5, –20). What is the y-coordinate of point L, which divides JK into a 7:3 ratio? a. –16

b.–11 c. –4 d.–1
Mathematics
2 answers:
babunello [11.8K]11 days ago
8 0
Let’s refer to the point that divides segment JK as point P; thus, segment JK gets separated into two segments, JP and PK.
PIT_PIT [12.4K]11 days ago
8 0
The answer is -11. To explain in detail: J = (–25, 10) K = (5, –20) Point L divides JK into a ratio of 7:3. To determine the coordinates for L, we will apply the section formula. Using the ratio m:n = 7:3. Replacing values yields: Hence, the y-coordinate of point L resolves to -11.
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Answer:

80 divided by 1000 multiplied by 20

Step-by-step explanation:

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1 month ago
The daily production cost, C, for x units is modeled by the equation:<br> C = 200 – 7x + 0.345x2
tester [12383]
C(x) = 200 - 7x + 0.345x^2

The domain consists of all feasible x-values (i.e., units produced), including all positive integers and zero, if only whole units are deemed relevant.

The range includes all potential outcomes for c(x), or possible costs.

This can be derived by recognizing that c(x) is a parabolic function, which can be graphed to identify the vertex, roots, y-intercept, and its shape (which opens upward since the coefficient of x^2 is positive). Also, ensure costs remain positive.

You might substitute some values for x for clarity, for example:

x y
0 200
1 200 - 7 + 0.345 = 193.345
2 200 - 14 + 0.345 (4) = 187.38
3 200 - 21 + 0.345(9) = 182.105
4 200 - 28 + 0.345(16) = 177.52
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6 200 - 42 + 0.345(36) = 170.42

10 200 - 70 + 0.345(100) = 164.5
11 200 - 77 + 0.345(121) = 164.745


The function lacks real roots, indicating costs will never fall to zero.

The function begins at c(x) = 200, declines until the vertex (x = 10, c = 164.5), and then starts to rise.

Thus, the range extends from 164.5 to infinity, limited to positive integer solutions for x.
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1 month ago
Desde una altura de 3m un chico patea verticalmente hacia arriba una pelota con una velocidad de 18m/s cual es su posicion 1 seg
AnnZ [12381]

Answer: The height is 13.1 m.

Step-by-step explanation:

The described motion is uniformly varied rectilinear, specifically vertical projectile motion.

To find the position after 1 second, we will use the motion equation expressed as:

y = v0.t - 1/2 g t^2

Here, y denotes the height at any given time.

v0 represents the initial velocity of 18 m/s.

g symbolizes the acceleration due to gravity at 9.81 m/s².

t indicates the time measured in seconds.

To calculate the height after one second:

y = 18 m/s x 1 sec - 1/2 9.81 m/s² (1 sec)² = 18 m - 4.9 m = 13.1 m

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1 month ago
Joel, a tutor at the Math Help, decided that it would be a good
PIT_PIT [12445]

Answer:

Joel achieved a peak height of 6 units.

Step-by-step explanation:

It appears there is an error in the equation representing Joel's jump. I will presume it should be h(t) = -0.2*t^2 + 2*t + 1, as such movements are typically represented using quadratic equations. To find the maximum height Joel attained, we must determine the vertex of this equation. The vertex for a quadratic can be found using the given expression:y(x) = a*x^2 + b*x + c

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Joel's highest point was 6 units.

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19 days ago
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Raymond utilized $65 from a total of $650, thus retaining $585.
650/10=65
650-65=585
alternatively (650/10)-65=585
the / indicates division. 
3 0
18 days ago
Read 2 more answers
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