The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.
For m₁: m₁*g - T = m₁*a
For m₂: T - m₂*g = m₂*a
Assuming a massless cord and pulley without friction, the accelerations are the same.
From the second equation: a = (T - m₂*g) / m₂
Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g
This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>
(a) The multiplicative inverse of 1234 (mod 4321) is x so that 1234*x ≡ 1 (mod 4321). We can apply Euclid's algorithm:
4321 = 1234 * 3 + 619
1234 = 619 * 1 + 615
619 = 615 * 1 + 4
615 = 4 * 153 + 3
4 = 3 * 1 + 1
Now we will express 1 as a linear combination of 4321 and 1234:
1 = 4 - 3
1 = 4 - (615 - 4 * 153) = 4 * 154 - 615
1 = 619 * 154 - 155 * (1234 - 619) = 619 * 309 - 155 * 1234
1 = (4321 - 1234 * 3) * 309 - 155 * 1234 = 4321 * 309 - 1082 * 1234
This reduces to
1 ≡ -1082 * 1234 (mod 4321)
Thus, the inverse is
-1082 ≡ 3239 (mod 4321)
(b) Since both 24140 and 40902 are even, their GCD cannot equal 1, indicating no inverse exists.
Let
s--------> denote the cube's side length
We know that
the volume of a cube is calculated as
if the side length s measures 
then
and thus, the volume is defined as
This leads us to conclude
the correct option is
D. A cube with side lengths of 2 feet has a volume of 8 cubic feet.
Answer:
Step-by-step explanation:
Given:
- Fuel volume = 5/6
- Each trip uses fuel = 1/12
- Number of trips to work = x
Since 1/12 of the tank is used for each trip and the starting volume is 5/6, the equation can be represented as:
By solving the equation, we find:
This means Felitz can make 10 trips to/from work with a tank filled to 5/6.
Answer:
60
Step-by-step explanation:
The function provided is:
The average rate of change of h(t) as time goes from t=a to t=b is expressed as:
This function can be reformulated as: 
The rocket's peak height is 231, which occurs at t=3.75 seconds.
The initial launch happens at: t=0
and 
The average rate of change from launch to max height is
÷