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matrenka
1 month ago
10

Ken has 7 baseballs. Each baseball weighs 0.3 pound . Ken wants to use this model to find the total weight of the baseballs. Eac

h hundredths block in the model represents 1 whole .

Mathematics
2 answers:
Zina [12.3K]1 month ago
8 0

Step-by-step explanation:

Given:

Ken owns 7 baseballs.

Each baseball weighs 0.3 pounds.

If one ball weighs 0.3 pounds,

then 7 baseballs weigh 7 × 0.3 pounds,

which sums to 2.1 pounds.

Therefore, the total mass of the 7 baseballs is 2.1 pounds.

To illustrate this using boxes as per the provided information:

Considering the weight involves decimals,

assign 1 square box as equivalent to 0.1 pounds.

Answer:

1. For a single baseball weighing 0.3 pounds, Ken should shade 3 boxes.

Since 1 box corresponds to 0.1 pounds,

3 boxes equal 0.3 pounds.

2. To depict the combined weight of seven baseballs (2.1 pounds), Ken must shade this set of boxes seven times.

This means shading 3 boxes per baseball, repeated 7 times.

This explains how the shaded area in the second part compares to the first.

3. The shaded model represents the expression 0.3 × 7.

4. The total weight of the baseballs is 2.1 pounds.

Inessa [12.5K]1 month ago
3 0

Answer:

Detailed explanation:

Given:

Ken owns 7 baseballs,

each weighing 0.3 pounds.

If 1 baseball weighs 0.3 pounds,

then 7 baseballs weigh 7 × 0.3 pounds,

which equals 2.1 pounds.

Therefore, the combined weight of the 7 baseballs is 2.1 pounds.

To illustrate this with boxes as specified,

note that the weights involve decimals.

Assign one square box to represent 0.1 pounds.

Answer:

1. Representing the weight of one baseball (0.3 pounds) requires shading 3 boxes.

Since 0.1 pounds equals 1 box,

3 boxes correspond to 0.3 pounds.

2. To depict the total weight for all seven baseballs (2.1 pounds), shade the 3 boxes seven times.

This means shading 3 boxes per baseball, repeated for all 7 baseballs.

This illustrates how the shading amount in the second part compares to the first part.

3. The shaded portion visually represents the multiplication 0.3 × 7.

4. The overall weight equals 2.1 pounds.

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Before the last school year began, it was estimated that the average discretionary personal expenses each school year for a stud
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Answer:

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Her expenses would need to be $1,625.00

Step-by-step explanation:

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The mean is defined as the average expense value, calculated as follows:

M=\frac{2,800+1,990+2,005+2,400+1,860+2,200+2,000}{7}\\M=2,179.29

2.) Is the average higher or lower than the estimate?

Given the estimate of $2,110, the average is indeed higher than this estimate.

3.)What amount of personal expenses would Ashley need to maintain a combined average of $2,110 with her friends' amounts for that school year?

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Her needed amount of expenses would be $1,625.00.

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Answer:

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Step-by-step explanation:

For a cubic shape with volume V, the edge length is defined as...

  s = ∛V

and the surface area is given by...

  A = 6s² = 6V^(2/3)

The area-to-volume ratio is therefore...

  r1 = A/V = 6V^(2/3)/V = 6V^(-1/3)

When the volume V is increased by a factor of 10, the new area-to-volume ratio becomes...

  r2 = 6(10V)^(-1/3)

Consequently, the change factor for the ratio is...

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The change in surface area per unit volume results in a factor of (∛100)/10.

___

Example

For a cube with side length 2, the corresponding volume equals 2³ = 8, with a surface area of 6·2² = 24. The resulting area-to-volume ratio is 24/8 = 3.

<pif we="" multiply="" the="" edge="" length="" by="" new="" volume="" equals="" and="" surface="" area="" equates="" to="" so="" area-to-volume="" ratio="" becomes...="">

The area-to-volume ratio changed by a factor of (0.3∛100)/3 = (∛100)/10, as previously noted.

</pif>
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1 month ago
There is a mound of g pounds of gravel in a quarry. Throughout the day, 400 pounds of gravel are added to the mound. Two orders
PIT_PIT [12445]

Question is Incomplete; Complete question is given below;

A pile of g pounds of gravel exists in a quarry. During the day, 400 pounds of gravel is added to the pile. Two orders of 900 pounds are removed, resulting in the mound holding 1,500 pounds of gravel by day's end. Formulate the equation that accurately illustrates this scenario.

Answer:

The equation that best represents the situation is g+400-1800=1300.

Step-by-step explanation:

Given:

Initial gravel amount = 'g'.

Currently Given:

Throughout the day, 400 pounds of gravel is added to the pile.

Thus we can conclude;

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Also given:

Two orders of 900 pounds are sold and the gravel is taken from the pile.

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Now Given:

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Therefore, we derive that;

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Consequently, the equation that best describes the scenario is g+400-1800=1300.

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