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NemiM
17 days ago
15

Enter a recursive rule for the geometric sequence. 6, −18, 54, −162, ...

Mathematics
1 answer:
PIT_PIT [3.9K]17 days ago
5 0

Answer:

The recursive formula needed is:

a_n=(-3)\times a_{n-1}

Detailed explanation:

We are given a geometric sequence:

6, -18, 54, -162, ...

By examining the terms, we see this sequence is a geometric progression (G.P.) with a common ratio, r, of -3.

Let a_n denote the nth term.

This implies:

a_1=6, a_2=-18, a_3=54, a_4=-162,......

Since the common ratio equals -3,

therefore,

a_1=6\\\\a_2=-18=(-3)\times a_1\\\\a_3=54=(-3)\times a_2\\\\.\\.\\.\\.\\.\\.\\.\\.\\.a_n=(-3)\times a_{n-1}

Thus, the recursive formula for this geometric sequence is:

a_n=(-3)\times a_{n-1}

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Which number line represents the solution set for the inequality –negative StartFraction one-half EndFraction x is greater than
Leona [4166]

Answer:

zero slope

Step-by-step explanation:

Hope this information is helpful:)

5 0
8 days ago
On a coordinate plane, 2 lines are shown. Line P Q has points (negative 8, 2) and (4, 2). Line M N has points (8, 6) and (8, neg
Svet_ta [4321]

Response:

PQ's slope is 0

MN's slope equals infinity

The lines PQ and MN are perpendicular to one another

Detailed explanation:

For two points in the coordinate plane, denoted as (x1, y1) and (x2, y2), the slope is determined as follows:

y1 - y2/x1-x2\\\\For \ line \ PQ\\slope = 2 - 2/-8-4 = 0\\\\For \ line \ MN \\slope = 6 - (-8)/8-8 = 1/0 = infinity\\\\

If a line has a slope of zero, it runs parallel to the X-axis and stands perpendicular to the Y-axis

If a line's slope is infinite, it is parallel to the Y-axis and perpendicular to the X-axis

Moreover, it is established that X and Y are perpendicular to each other.

As PQ's slope is zero, it runs parallel to the X-axis and perpendicular to the Y-axis

With MN having an infinite slope, it runs parallel to the Y-axis and perpendicular to the X-axis.

Therefore, lines PQ and MN are indeed perpendicular.

4 0
6 days ago
Read 2 more answers
Rob borrows $15.00 from his father, and then he borrows $3.00 more. Drag numbers to write an equation using negative integers to
PIT_PIT [3919]

Answer:

Rob's total debt to his father is calculated as: -$15 - $3 = -$18

Step-by-step explanation:

Initially, Rob borrows $15.

Then, he borrows an additional $3.

Expressing this with negative integers gives us

-15 - 3 = -18

4 0
5 days ago
Read 2 more answers
Determine the rate of change for the equation.<br> 6y = 8x - 40
Leona [4166]
The answer is 4/3, which represents the rate of change. Going up 3 and moving over 4.
4 0
6 days ago
Find a vector parametrization of the ellipse centered at the origin in the xy-plane that has major diameter 8 along the x-axis,
zzz [4022]

Answer:

E(t) = [ 4cos(t), 2 sin(t) ]

Step-by-step explanation:

The equation for the ellipse can be represented as:

 (x² ÷ a² ) + (y² ÷ b² ) = 1    Here, a and b symbolize the semi-major and semi-minor axes.

In this specific instance, we have    x²/16 + y²/ 4 = 1

This expression indicates that it follows the form of (x/a)² + (y/b)² =1

Specifically in our case,    x²/16  + y²/4 = 1, which resembles                 sin²α + cos²α = 1.

By setting x = 4 cos(t), we can proceed to calculate y.

Utilizing the equation x²/16  + y²/4 = 1, we find that:

x²/16  + y²/4 = 1   ⇒    (x²  +  4y²) ÷ 16  = 1

Solving for y yields: (x²  +  4y²)  = 16    ⇒  y²  = ( 16 - x²) ÷4

Substituting x = 4 cos(t) gives us y²  =  (16 - 16cos²(t)) ÷ 4, leading to y = √4 (1 - cos²(t)).

Consequently, we have y = 2 sin(t).

Thus, the vector parameterization of the ellipse can be stated as:

E(t) = [ 4cos(t), 2 sin(t) ]

3 0
6 days ago
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