The solutions to the equation are 
Explanation:
Given the equation 
, we aim to find the solutions of the equation.
Let us use
and 
Thus, the equation transforms into

Factoring the equation results in:


Inserting back
and allows us to solve for x.
Initially, we will substitute 
Consequently, we find;



Similarly, by substituting
, we derive;



Thus, the solutions to the equation are 
The watch is less expensive in Geneva, Switzerland by £20. Step-by-step explanation: To identify the city where the watch is cheaper, we need to convert the watch's price to the same currency. Since pounds are utilized in part b of the question, using this currency would simplify the calculations. In Geneva, the watch's price is 193.75 CHF from our conversion: £1 = 1.55 CHF, thus, £x = 193.75 CHF. By cross-multiplying, we solve for x: (193.75 * 1) / 1.55 = 193.75/1.55 = £125. This demonstrates that the watch is cheaper in Geneva and more expensive in Manchester. To find out by how much, we simply deduct the Geneva price from the Manchester price: 145 - 125 = £20 cheaper.
We opt to accept the null hypothesis. Given the following details provided: the Sample mean equals 28.8 miles per gallon, Sample size n is 120, and Alpha α is 0.01 with a sample standard deviation of 6.89 miles per gallon. Initially, we set up the null and alternative hypotheses. Utilizing a two-tailed t-test facilitates this hypothesis testing. By substituting the relevant values we calculate, and eventually conclude that we fail to reject the null hypothesis, endorsing that the average MPG for the Toyota Highlander Hybrid vehicles is indeed 28 miles per gallon.
To achieve the desired output, first use the machine with the function y = x^2 - 6, followed by the machine that computes y = sqrt(x-5). This way, when you input 6, the output from the first machine is calculated as x = 6, yielding y = 6^2 - 6, resulting in 30 as the input for the second machine. The second machine then processes this to provide the final output of sqrt(30 - 5), which equals sqrt(25) = 5. Alternatively, to obtain a negative final output, you should first utilize the machine with the function y = sqrt(x-5). Assuming you start with the value x = 9, the first machine computes this to sqrt(9-5), which is sqrt(4) = 2. Then, the second machine converts y to 2^2 - 6, leading to a result of 4 - 6 = -2.