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liubo4ka
1 month ago
9

Ezra counts the number of passengers who are already on the bus when he gets on each morning. His data for the last 15 days are

shown below. What is the interquartile range of the data? 8, 9, 9, 10, 12, 12, 13, 14, 15, 15, 15, 16, 18, 19, 20
Mathematics
1 answer:
Zina [12.3K]1 month ago
8 0

Response:

I believe the answer is 6.

Detailed breakdown:

First, you need to identify both the upper and lower quartiles.

The upper quartile equals 10.

The lower quartile equals 16.

Next, subtract the lower quartile from the upper quartile, resulting in 6.

Your answer is 6.

If you need further assistance, feel free to ask!

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Joe wants to enlarge the rectangular pumpkin patch located on his farm. The pumpkin patch is currently 40 meters wide and 60 met
PIT_PIT [12445]

Answer:

The area of the new pumpkin patch can be represented as  Area_2  =  15 x² + 380 x + 2400

Step-by-step explanation:

Given as:

The length of the original patch is L = 40 meters

The width of the original patch is W = 60 meters

Thus, the area of the rectangular patch is calculated as Length × Width

Or, Area_1 =  L × W

So,  Area_1  =  40 meters × 60 meters

Or,  Area_1 =  2400 meters²

Moreover, the width of the new patch becomes (40 + 3 x) meters

And the length of the new patch becomes (60 + 5 x) meters

Or, Area_2  =  L × W

Thus,Area_2  =  (40 + 3 x) meters × (60 + 5 x) meters

Or,  Area_2  = 2400 + 200 x + 180 x + 15 x²

Or,  Area_2  =  15 x² + 380 x + 2400

Therefore, the area of the new pumpkin patch is given by  Area_2  =  15 x² + 380 x + 2400  Answer

8 0
22 days ago
Kevin is buying water for his camping trip. He knows he needs at least 20 gallons of water for the trip. He already has five and
PIT_PIT [12445]

Response:

5.5+0.25x\geq 20

Step-by-step breakdown:

Kevin has already gathered five and a half gallons of water for his trip

He understands that he requires a minimum of 20 gallons of water for the journey.

The water is packaged in 32-fluid ounce (quarter-gallon) containers.

1 fluid ounce equals 0.0078125 gallons

32-fluid ounce =32 \times 0.0078125 =0.25

Let x represent the number of 32-fluid ounce (quarter-gallon) containers needed to collect at least 20 gallons of water for the trip.

One container holds 0.25 gallons of water

Therefore, x containers hold 0.25x gallons of water

Thus, Kevin's total gallons of water =5.5+0.25x

Since it is given that he needs at least 20 gallons of water for the trip.

Hence, 5.5+0.25x\geq 20

Thus, the algebraic inequality representing this scenario is 5.5+0.25x\geq 20

5 0
27 days ago
Read 2 more answers
A rectangular prism must have a base with an area of no more than 27 square meters. The width of the base must be 9 meters less
Leona [12618]

Answer:

The upper limit for the height of the prism is 12\ m

Step-by-step explanation:

Let

x------> represent the height of the prism

It is known that

the area of the base of the prism must not exceed

A=L*W

A\leq 27\ m^{2}

thus

L*W\leq 27 -------> inequality A

W=x-9 ------> equation B

L=W+6 -----> equation C

Insert equation B into equation C

L=(x-9)+6

L=x-3 ------> equation D

Substituting equations B and D into inequality A

(x-3)*(x-9)\leq 27-------> using a graphing tool to solve the inequality

The resultant solution for x lies in the interval---------->[0,12]

consult the attached figure

but bear in mind that

The width of the base must be 9 meters shorter than the height of the prism

thus

the solution for x is confined to the interval ------> (9,12]

The maximum height of the prism equals 12\ m

8 1
1 month ago
Read 2 more answers
−4x+60<72 or 14x+11<−31 solve for x
Leona [12618]
The answer to your question is x = 8
5 0
1 month ago
Read 2 more answers
If rs 500 amounts to Rs 725 at 9% simple interest in sometime ,what will Rs 600amount to at 11% in same time?
AnnZ [12381]

Answer:

Rs\ 930

Step-by-step explanation:

The formula for calculating simple interest is

A=P(1+rt)

Here,

A refers to the Total Amount of Investment

P denotes the Initial Investment

r indicates the interest rate 

t represents the duration in time periods

step 1

Determine the duration t

For this scenario, we have

t=?\ years\\ P=Rs\ 500\\ A=Rs\ 725\\r=0.09

Plugging into the formula above and solving for t

725=500(1+0.09t)

t=[(725/500)-1]/0.09

t=5\ years

step 2

What will Rs 600 grow to at 11% over the same duration?

We have

t=5\ years\\ P=Rs\ 600\\ A=?\\r=0.11

Insert into the formula

A=600(1+0.11*5)

A=600(1.55)

A=Rs\ 930

6 0
1 month ago
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