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Stells
12 days ago
15

One of the most recognizable corrosion reactions is the rusting of iron. rust is caused by iron reacting with oxygen gas in the

presence of water to create an oxide layer. iron can form several different oxides, each having its own unique color. red rust is caused by the formation of iron(iii) oxide trihydrate. in the space provided, write the balanced reaction for the formation of fe2o3•3h2o(s). phases are optional.
Chemistry
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5 grams of NaHCO3 was added to 50 cm3 of 1.5 mol dm-3 hydrochloric acid, causing the temperature to decrease by 6.8 K. What is t
Anarel [2989]

The balanced chemical equation for the neutralization of HCl with NaHCO_{3} is:

HCl (aq) + NaHCO_{3}(aq)--> NaCl (aq) + H_{2}O(l)+CO_{2} (g)

Given weight of NaHCO_{3} = 5g

Moles of NaHCO_{3} = 5 g *\frac{1 mol}{84 g} = 0.05952 mol NaHCO_{3}

Volume of HCl solution = 50 cm^{3} * \frac{1 mL}{1cm^{3}} = 50 mL

Assuming the density of the solution is 1.0 g/mL

Mass of HCl solution = 50 g

Overall mass of the solution = 50 g + 5 g = 55 g

To find the heat of neutralization, we calculate:

Q = m C ΔT

where m equals the mass of the solution = 55 g

C represents the specific heat capacity of the solution = 4.184\frac{J}{g. ^{0}C}

ΔT signifies the temperature change = 6.8 K = (6.8 - 273) C = -266.2^{0}C

Q = 55 g * 4.184 \frac{J}{g. K}(6.8K) = 1565 J

The enthalpy of neutralization per mole of NaHCO_{3}

= \frac{1565J}{0.05952 mol} = 26294 \frac{J}{mol}*\frac{1 kJ}{1000J} =26.294kJ/mol

3 0
3 months ago
Read 2 more answers
Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversi
Tems11 [2777]

Answer:

15.71g

Explanation:

The combustion equation that applies to hydrocarbons is

CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O

In the case of octane, C8H18:

C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O

C8H18 + 50/4 O2 = 8CO2 + 9H2O

C8H18 + 25/2 O2 = 8CO2 + 9H2O

2C8H18 + 25 O2 = 16 CO2 + 18H2O (this is the balanced equation)

From this balanced reaction,

2 x 22.4 L of octane generates 16 [ 12 + (16 x 2)] of carbon dioxide

That means,

44.8 L of octane generates 704g of carbon dioxide

Thus, for 1L of octane, it produces 1 L x 704g/44.8 L = 15.71g of carbon dioxide

Consequently, 15.71g of carbon dioxide is produced from the complete combustion of 1 L of octane.

7 0
2 months ago
Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3
Tems11 [2777]
The work done is 19.26 kJ.
5 0
1 month ago
A sample of a compound that contains only the elements C, H, and N is completely burned in O2 to produce 44.0 g of CO2, 45.0 g o
alisha [2963]

Clarification:

To obtain the specific element, you should multiply the grams provided by the ratio of grams of that particular element within its complete compound.

Since the query did not indicate the amount of NO2 produced, we can consider its mass to be negligible, thus assigning 1 mole to Nitrogen.

3 0
2 months ago
Be sure to answer all parts. The sulfate ion can be represented with four S―O bonds or with two S―O and two S═O bonds. (a) Which
Anarel [2989]

Response:

a) Representation - (in attachment)

b) The geometry is tetrahedral

c) sp^{3} hybrid orbitals involve sigma bonding.

\pi orbitals arise from the overlap of sulfur's d-orbitals with the p-orbitals of oxygen.

Clarification:

a)

Representation in attachment.

The total charge in both structures is -2. Structure (b) is preferred according to the resonance forms since the formal charges within the species are preserved.

Thus, structure (b) represents the sulfate ion more accurately.

b) In the sulfate ion, the sulfur atom forms connections with four distinct oxygen atoms. Using VSEPR theory, the sulfate ion is tetrahedral in shape.

There are four sigma bonds and no lone pairs surrounding the central atom.

Consequently, the sulfur atom's hybridization is sp^{3}

c)

The s and p orbitals of sulfur undergo hybridization to form sigma bonds. The orbitals involved in \pi bonding are

Therefore, \pi bonds result from the overlapping of sulfur's d-orbitals with the p-orbitals of oxygen.

5 0
2 months ago
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