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2 months ago

What is the percentage by mass of solution formed by dissolving 36.0 grams of HCl in 98.0 grams of water?

Chemistry

2 answers:

Alekssandra [3K]2 months ago

5 0

Answer:

The mass percentage of the solution is 26.86%.

Explanation:

Hydrochloric acid mass = 36.0 g

Water mass = 98.0 g

The solution is composed of HCl and water.

Total mass of the solution = 36.0 g + 98.0 g = 134 g

Mass percentage of the solution:

$\frac{\text{Mass of solute}}{\text{Mass of the solution}}\times 100$

$\frac{36 g}{134 g}\times 100=26.86\%$

The mass percentage of the solution is 26.86%.

eduard [2.7K]2 months ago

4 0

Convert HCl and H2O to moles.

36.0 g of HCl = 0.987 moles HCl

98.0 g of H2O = 5.44 moles H2O

Based on the stoichiometric ratio for HCl,
there are 0.987 moles of H and 0.987 moles of Cl.

For H₂O, according to the stoichiometric ratio, you have 10.88 moles of H and 5.44 moles of O.

Combining them:
11.867 moles H
0.987 moles Cl
5.44 moles O

Revert the moles back to grams, then divide by the total mass and multiply by 100 for the percentage by mass.

11.867 moles H = 11.96 g H
0.987 moles Cl = 34.99 g Cl
5.44 moles O = 87.03 g O

11.96/(36.0+98.0)(100) = 8.93% for H
34.99/(36.0+98.0)(100) = 26.11% for Cl
87.03/(36.0+98.0)(100) = 64.96% for O.

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Clarification:

The pertinent information is outlined as follows.

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$2T_{f} = 100^{o}C$

$T_{f} = 50^{o}C$

It's important to convert the temperature into Kelvin as (50 + 273) K = 323 K.

Additionally, the relationship between enthalpy and temperature change is as follows.

$\Delta H = mC \Delta T$

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or, = 1243.5 kJ

Next, determine the entropy change for block 1 as follows.

$\Delta S_{1} = mC ln \frac{T_{f}}{T_{i}}$

= $10000 g \times 0.385 J/K g \times ln \frac{323}{373}$

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= -554.12 J/K

Now, the entropy change for block 2 is as follows.

$\Delta S_{2} = mC ln \frac{T_{f}}{T_{i}}$

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= 647.49 J/K

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