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wariber
5 days ago
5

In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of

Fe. What is the formula of the oxide?
Chemistry
1 answer:
castortr0y [918]5 days ago
5 0

Answer:

The oxide formula is Fe_{2}O_{3}

Explanation:

The provided compound contains iron (Fe) and oxygen (O).

Therefore, mass of oxygen in the sample = (total mass) - (mass of iron)

                                                   = (6.285 g) - (4.396 g)

                                                   = 1.889 g

Molar mass of oxygen = 16 g/mol and of iron = 55.845 g/mol.

Thus, the ratio of moles of Fe and O (Fe: O)

      = \frac{4.396}{55.845}:\frac{1.889}{16}

      = 0.0787: 0.118

      = 1:\frac{0.118}{0.0787}

      = 1: 1.5

      = 2: 3.

Consequently, the oxide formula is Fe_{2}O_{3}.

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Answer:

This indicates that the enzyme is a type of protein.

Explanation:

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However, when they form a polymer, the protein enzyme will possess varying shapes, sizes, and both physical and chemical attributes differing from a single monomer.

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8 0
4 days ago
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A chemist is studying the following reaction: NO + NO2 ⇌ N2O3. She places a mixture of NO and NO2 in a sealed container and meas
castortr0y [918]

Answer:

The forward reaction will keep occurring until all NO or all NO₂ is consumed.

Clarification:

  • According to Le Châtelier's principle, when a system at equilibrium experiences a disturbance from an outside source, the system will adjust to counteract this disturbance and restore equilibrium.

  • Thus, removing the product (N₂O₃) from the system effectively lowers the product concentration, prompting the reaction to shift forward and generate additional product in order to alleviate the strain caused by the removal of N₂O₃.

  • Consequently, the reaction will proceed forward until all of either NO or NO₂ is depleted.

5 0
2 days ago
What volume of gold would be equal in mass to a piece of copper with a volume of 141 ml? the density of gold is 19.3 g/ml; the d
alisha [964]

We need to calculate the volume of Gold, assuming its mass matches that of copper.

Given information:

Density of Copper = 8.96 g/ml.
Volume of Copper = 141 ml.
Mass of Gold = Mass of Copper.
Density of Gold = 19.3 g/ml.

To find copper's mass, we use the density equation:
Density = mass/volume.

To find mass of copper:
Mass of copper = Density of Copper * Volume of Copper.
Mass of copper = 8.96 g/ml * 141 ml = 1263.36 g.
Thus,
Mass of gold = Mass of copper = 1263.36 g.
Now, using the density formula for gold to get its volume:
Volume of gold = Mass of gold / Density of gold.
Volume of gold = 1263.36 g / 19.3 g/ml = 65.46 mL.

Consequently, the volume of gold required to match the mass of copper is 65.46 mL.

8 0
4 days ago
Based on the bond energies for the reaction below, what is the enthalpy of the reaction?HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O
alisha [964]

Answer:

1219.5 kJ/mol

Explanation:

The calculation for this value requires using the following equation:

ΔHºrxn = Σn * (BE of reactants) - Σn * (BE of products)

ΔHºrxn = [1 * (BE C = C) + 2 * (BE C-H) + 5/2 * (BE O = O)] - [4 * (BE C = O) + 2 * (BE O-H)].

The bond energy (BE) values are:

BE C = C: 839 kJ/mol

BE C-H: 413 kJ/mol

BE O = O: 495 kJ/mol

BE C = O: 799 kJ/mol

BE O-H: 463 kJ/mol

By substituting these values into the equation, you will get:

ΔHºrxn = [1 * 839 + 2 * (413) + 5/2 * (495)] - [4 * (799) + 2 * (463)] = 1219.5 kJ/mol

8 0
5 days ago
Which of the following happens during an endothermic chemical change? (5 points)
lorasvet [946]

Answer:

Heat is absorbed.

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7 days ago
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