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suter
1 month ago
6

At -70 ∘c and 5.2 atm, carbon dioxide is in which phase?

Chemistry
2 answers:
Tems11 [2.7K]1 month ago
7 0

A phase diagram illustrates the relationship between temperature and pressure, allowing determination of a compound's phase under specific conditions. The three equilibrium curves: Solid-Gas, Liquid-Gas, and Solid-Liquid, separate the different states of matter. Additionally, all three phases can coexist at a specific point known as the triple point.

According to the phase diagram for CO2 (easily found online), at -70 C and 5.5 atm, CO2 is in a solid state.


castortr0y [3K]1 month ago
6 0
The conversion of -70 degrees Celsius results in 9/5 x C + 32 = 158 degrees Fahrenheit. CO2 transitions to solid state at -108.5 degrees Fahrenheit, indicating that at -70 degrees Celsius, it will be in the state commonly known as 'dry ice'.
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Which of the following could be considered a scientific statement?
Anarel [2989]

Answer: D) X-rays exhibit lower frequency than microwaves

Explanation:

A scientific statement is one that relies on evidence gathered from experiments and direct observation of the natural world. Such a statement can be corroborated through appropriate experimental methods.

The option D illustrates a scientific statement because it allows for the frequency of both microwaves and X-rays to be assessed and contrasted. This process entails experimental and observational techniques, which validates it as a scientific statement.

6 0
1 month ago
Read 2 more answers
What mass of carbon dioxide (co2) can be produced from 86.17 grams of c6h14 and excess oxygen?
lorasvet [2795]
2C6H14 + 13O2 ---> 6CO2 +14H2O

Calculating the molar mass of C6H14: M(C6H14)=12.011*6 +1.008*14 ≈ 86.17 g/mol

Thus, 86.17 g of C6H14 corresponds to 1 mole.

                                  2C6H14 + 13O2 ---> 6CO2 +14H2O
based on the equation        2 mol                            6 mol
according to the question    1 mol                            3 mol

To determine M(CO2): M(CO2)= 12.011 + 2*15.999= 44.009 g/mol
Therefore, 3 mol CO2*44.009 g/1 mol CO2 ≈ 132.0 g CO2
Final answer: 132.0 g CO2


3 0
1 month ago
The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when
castortr0y [3046]

Answer: The cell potential for the given reaction stands at 0.50 V

Explanation:

The provided cell reaction is:

Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)

The half-reactions are:

Anode oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Cathode reduction half reaction:  Pb^{2+}+2e^-\rightarrow Pb

Initially, we need to find the cell potential for this reaction.

Utilizing the Nernst equation:

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}

where,

F = Faraday's constant = 96500 C

R = gas constant = 8.314 J/mol·K

T = room temperature = 25^oC=273+25=298K

n = electrons exchanged in oxidation-reduction = 2

E^o_{cell} = standard electrode potential for the cell = +0.63 V

E_{cell} = cell potential for the reaction =?

[Zn^{2+}] = concentration of Zn²⁺ = 3.5 M

[Pb^{2+}] = 2.0\times 10^{-4}M

Now substituting all known values into the equation, we arrive at:

E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}

E_{cell}=0.50V

So, the resulting cell potential for this reaction is 0.50 V

5 0
18 days ago
5. Gabi has plans with her friends to go to a concert on her birthday in 4 days. She is so excited that she wants to know how ma
Alekssandra [3086]
Consequently, she feels very anxious because she has 345600 seconds to wait. Explanation: 60 seconds make up 1 minute, and 60 minutes constitute an hour. Each hour has 3600 seconds (60*60) and 24 hours make up a day. Hence, 3600 seconds multiplied by 24 hours results in 1 day equating to 86400 seconds—therefore, over four days, we have 86400 * 4 equating to 345600.
7 0
22 days ago
An experimenter studying the oxidation of fatty acids in extracts of liver found that when palmitate (16:0) was provided as subs
eduard [2782]

Answer:

Fatty acids with an even number of carbons, like palmitate, undergo complete β-oxidation in the liver mitochondria, resulting in CO₂, as acetyl-CoA, their end product, can enter the TCA cycle.

On the other hand, odd-number fatty acids such as undecanoic acid generate acetyl-CoA and propionyl-CoA during their final pass. To allow entry into the TCA cycle, propionyl-CoA must go through additional processes, including carboxylation.

The conversion of CO2 and propionyl-CoA into methylmalonyl-CoA is facilitated by propionyl-CoA carboxylase, a biotin-dependent enzyme that is inhibited by avidin. In contrast, the oxidation of palmitate does not require carboxylation.

Explanation:

Fatty acids with an even number of carbons, such as palmitate, are completely oxidized to CO₂ in the liver mitochondria due to the ability of their oxidation product, acetyl-CoA, to enter the TCA cycle where it is further oxidized to CO₂.

Undecanoic acid is classified as an odd-number fatty acid, consisting of 11 carbon atoms. The last stage of β-oxidation for odd-number fatty acids, like undecanoic acid, produces a five-carbon fatty acyl substrate that is oxidized and split into acetyl-CoA and propionyl-CoA. To enter the TCA cycle, propionyl-CoA needs additional reactions such as carboxylation. Since the oxidation occurs using a liver extract, CO₂ must be supplied externally for propionyl-CoA carboxylation, enabling the complete oxidation of undecanoic acid.

The conversion of CO2 and propionyl-CoA into methylmalonyl-CoA is catalyzed by propionyl-CoA carboxylase, which contains biotin. The function of biotin is to activate CO₂ before it is transferred to the propionate group. The addition of avidin obstructs the complete oxidation of undecanoic acid as it binds very tightly to biotin, thereby hindering the activation and transfer of CO₂ to propionate.

In contrast, palmitate oxidation does not require carboxylation, meaning that the presence of avidin doesn't influence its oxidation.

6 0
16 days ago
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