The largest number which divides 60 and 75, leaving remainders 8 and 10 respectively is? Please I need an answer with a full exp

Answer:

The cost difference per mile between the two companies is $0.12.

Step-by-step explanation:

Gabi formulates the equation to determine after how many miles, denoted as m, the charges of both companies will be equal.

The first company levies for m miles traveled.

The second company's charge for the same m miles is .

In these equations, the figures 7.20 and 8.40 signify the initial fees the companies impose.

The values 0.22 and 0.1 represent the respective costs per mile.

As such, the disparity in per-mile charges amounts to .

An alternative method to tackle this problem is by calculating the per-mile rate for each company:

1. Cost per mile for the first company

2. Cost per mile for the second company

3. The difference:

There are a total of 20,000 available numbers. To ascertain how many phone numbers are available, the number of digits in each number must be known. Here, I will assume each number has 7 digits. This leads to the format starting with either 373XXXX or 377XXXX, where each X can be any digit from 0 to 9. This results in 10 options for each X. Therefore, there are 10×10×10×10 = 10,000 distinct phone numbers starting with 373 and another 10,000 with 377, totaling 20,000 numbers.

5(11 squared + 1) plus 16

5(121 + 1) plus 16

5(122) plus 16

605 plus 16

p(11) equals 626

In each instance, when it sheds a shell, its size increases by a factor of 1 1/3. To determine the growth after the first molt, multiply 1 cm by 1 1/3 to get 1 1/3 cm. To find the next size, repeat the multiplication: 1 1/3 cm times 1 1/3 cm equals 16/9. This process will continue by multiplying by 1 1/3. We can express it mathematically as (initial size) * 1 1/3 *(number of shells) equals length or 1 cm * 1 1/3 * n equals L. Given that the final length is 10 cm, accordingly, 1 1/3 * n equals 10 cm, leading to n being 7.5 shells, which translates to either about 7 or 8 shells.

The equation that demonstrates a proportional relationship, maintaining a constant of proportionality equal to 14, is: Here,  and are proportional with a constant of proportionality of 14.