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13 days ago

A small town's phone numbers either begin 373 or 377. How many phone numbers are available?

1 answer:

6 0

There are a total of 20,000 available numbers. To ascertain how many phone numbers are available, the number of digits in each number must be known. Here, I will assume each number has 7 digits. This leads to the format starting with either 373XXXX or 377XXXX, where each X can be any digit from 0 to 9. This results in 10 options for each X. Therefore, there are 10×10×10×10 = 10,000 distinct phone numbers starting with 373 and another 10,000 with 377, totaling 20,000 numbers.

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if a student scored 78 points on a test where the mean score was 84.5 and the standard deviation was 3.1. the student's z score

Inessa [8989]

Answer:

(value - mean)/standard deviation.

Now substitute 78 for the value, 84.5 for the mean, and 3.1 for the standard deviation.

Step-by-step explanation:

5 0

25 days ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

Inessa [8989]

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format $y/x=k$ or $y=kx$

For this question, we have

the point $(5,12)$ lies on the direct variation line

therefore

Determine the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

The equation is

$y=\frac{12}{5}x$

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point $(0,0)$

$x=0\ y=0$

Insert the values of x and y into the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is valid

thus

the point $(0,0)$ lies on the direct variation line

case B) point $(2.5,6)$

$x=2.5\ y=6$

Insert the values of x and y into the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is valid

thus

the point $(2.5,6)$ lies on the direct variation line

case C) point $(3,10)$

$x=3\ y=10$

Insert the values of x and y into the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not valid

thus

the point $(3,10)$ does not lie on the direct variation line

case D) point $(7.5,18)$

$x=7.5\ y=18$

Insert the values of x and y into the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is valid

thus

the point $(7.5,18)$ lies on the direct variation line

case E) point $(12.5,24)$

$x=12.5\ y=24$

Insert the values of x and y into the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not valid

thus

the point $(12.5,24)$ does not lie on the direct variation line

case F) point $(15,36)$

$x=15\ y=36$

Insert the values of x and y into the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is valid

thus

the point $(15,36)$ lies on the direct variation line

ultimately

the solution is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

24 days ago

Read 2 more answers

Diego's club earns money for charity when members of the club perform community service after school,

babunello [8402]

Answer: Indeed, because the input value ranges from 0 to 12.

Step-by-step explanation:

To address this query, we first need to formulate a function that reflects the situation.

Every student engaging in community service earns the club $5

E(s) = 5 s

Where:

E= total earnings
n = number of students participating in community services (input value)

Indeed, since the input value n indicates how many students from the club engage in community service, and with the total number of students being 12, the input can indeed vary between 0 and 12.

6 0

19 days ago

Two players A and B play a marble game. Each player has both a red and blue marble. They present one marble to each other. If bo

Zina [9157]

Answer:

Step-by-step explanation:

Player A has a red marble and a blue marble, while Player B also has a red marble and a blue marble.

Therefore, the probability of selecting one marble is equal, at 0.5.

Due to the independence of A and B's choices, the joint event is calculated by multiplying the probabilities.

Let A represent the amount that player A wins.

If both players select one marble, the sample space can be considered as

(R,R) (R,B) (B,R) (B,B)

Probability 0.25 0.25 0.25 0.25

A's winnings 3 -2 -2 1

E(A) 0.75 -0.5 -0.5 0.25 = 0

Thus, the game is even, offering equal expected values for both A and B.

It does not influence the outcome whether you are A or B.

5 0

1 month ago

A recipe calls for 1 1/4 cups of flour, 3/4 cup of white sugar, and 1/3 cup of brown sugar. The recipe makes 4 servings. How man

PIT_PIT [9101]

Answer:

See explanation.

Step-by-step explanation:

Flour:

1 1/4 cups equals 5/4 cups.

5/4 divided by 4 yields 5/4 times 1/4.

= 5/16 cups of flour for each serving.

Sugar (Brown):

1/3 cup divided by 4 gives 1/3 times 1/4.

= 1/12 cups of brown sugar per serving.

Sugar (White):

3/4 divided by 4 results in 3/16 cups per serving.

For 6 servings:

Flour: 5/16 times 6 equals 1 7/8 cups.

Sugar (Brown): 1/12 times 6 results in 1/2 cup.

Sugar (White): 3/16 times 6 equals 1 1/8 cups.

3 0

21 day ago