Jonah stacks balls of yarn in a square pyramid for a store display. The number of balls of yarn, P(n), in "n" layers of a square

The time between failures for an electrical appliance is exponentially distributed with a mean of 25 months. What is the probabi

Inessa [12570]

Answer:

The likelihood that a failure will not take place within the next 30 months is 0.0454.

Step-by-step explanation:

We employ a Poisson distribution where:

t = time units

x = occurrences during t units

λ = average occurrences per unit of time

P(x;λt) = e raised to the power of (-λt) multiplied by λtˣ divided by x!

Here, λt equals 25.

x equals 30.

P(x= 30) = 25³⁰e⁻²⁵/ 30!

P (x= 30) = 8.67 E41 * 1.3887 E-11/30! (where E signifies exponent)

P (x=30) = 1.204 E31/30!

Utilizing a statistical calculator will yield:

P (x=30) = 0.0454

The probability that the next failure will not occur prior to 30 months is 0.0454.

7 0

2 months ago

How does the graph of mc024-1.jpg compare to the graph of the parent function mc024-2.jpg?

babunello [11817]

The question is as follows:
In what ways does the graph of g(x)=1/x-5+2 differ from the graph of the parent function f(x)=1/x?

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Solution:
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The given function ⇒ $g(x) = \frac{1}{x-5} +2$

The parent function of the provided function ⇒ $f(x)= \frac{1}{x}$

After graphing both equations, as illustrated in the attached image.
It can be concluded that
g(x) is translated 5 units to the right and 2 units upwards from f(x).


Thus, the correct answer is option 2

6 0

2 months ago

Read 2 more answers

Match each pair of points to the equation of the line that is parallel to the line passing through the points.

Svet_ta [12734]

It's known that

When two lines are parallel, their slopes are identical.

The slope between any two points can be calculated using the following formula:

$m=\frac{y2-y1}{x2-x1}$

We will calculate the slope for each case to find the solution to the problem.

Case A) Point $B(5,2)\ C(7,-5)$

Determine the slope of BC

Insert the values into the formula:

$m=\frac{-5-2}{7-5}$

$m=\frac{-7}{2}$

$m=-3.5$

Thus,

The equation $y=-3.5x-15$ is parallel to the line that goes through the points $B(5,2)\ C(7,-5)$

Therefore,

the result for Part A) is

$B(5,2)\ C(7,-5)$ ------> $y=-3.5x-15$

Case B) Point $D(11,6)\ E(5,9)$

Calculate the slope of DE

Plug the values into the formula:

$m=\frac{9-6}{5-11}$

$m=\frac{3}{-6}$

$m=-0.5$

Thus,

The equation $y=-0.5x-3$ is parallel to the line that goes through the points $D(11,6)\ E(5,9)$

Therefore,

the result for Part B) is

$D(11,6)\ E(5,9)$ ------> $y=-0.5x-3$

Case C) Point $F(-7,12)\ G(3,-8)$

Determine the slope of FG

Insert the values into the formula:

$m=\frac{-8-12}{3+7}$

$m=\frac{-20}{10}$

$m=-2$

Thus,

Any linear equation with slope $m=-2$ will be parallel to the line through the points $F(-7,12)\ G(3,-8)$

Case D) Point $H(4,4)\ I(8,9)$

Calculate the slope of HI

Substitute the values in the formula:

$m=\frac{9-4}{8-4}$

$m=\frac{5}{4}$

$m=1.25$

Thus,

The equation $y=1.25x+4$ is parallel to the line through the points $H(4,4)\ I(8,9)$

Therefore,

the result for Part D) is

$H(4,4)\ I(8,9)$ ------> $y=1.25x+4$

Case E) Point $J(7,2)\ K(-9,8)$

Determine the slope of JK

Insert the values into the formula:

$m=\frac{8-2}{-9-7}$

$m=\frac{6}{-16}$

$m=-0.375$

Thus,

Any linear equation characterized by slope $m=-0.375$ will be parallel to the line that runs through the points $J(7,2)\ K(-9,8)$

Case F) Point $L(5,-7)\ M(4,-12)$

Find the slope of LM

Substitute the values in the formula:

$m=\frac{-12+7}{4-5}$

$m=\frac{-5}{-1}$

$m=5$

Thus,

The equation $y=5x+19$ is parallel to the line connecting the points $L(5,-7)\ M(4,-12)$

Therefore,

the result for Part F) is

$L(5,-7)\ M(4,-12)$ ------> $y=5x+19$

8 0

2 months ago

Read 2 more answers

Rajan had 6000 RS in his bank account on a particular day a week later he deposited 150p RS and next day he had withdraw 1/3rd o

babunello [11817]

Answer: After the withdrawal, Rajan's bank balance will be

6150 RS - 2050 RS = 4100 RS

Step-by-step explanation:

Initially, Rajan had 6000 RS in his bank account about a week ago. This indicates that the initial balance he possessed is 6000 RS.

One week later, he credited 150p RS to his account.

Thus, the current total in his account is

= 6000 RS + 150p RS = 6150 RS.

The following day, he withdrew one-third of his total balance. Therefore, the amount withdrawn is

1/3 × 6150 = 6150/3 = 2050 RS

After the withdrawal, his remaining balance in the bank will be the new total minus the amount withdrawn.

His remaining balance in the bank account post-withdrawal will be

6150 RS - 2050 RS = 4100 RS

4 0

2 months ago