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alexgriva
1 month ago
6

Barbiturates, including "truth serums" seen in movies like Meet the Fockers and sedatives that may have led to the untimely deat

h of Jimi Hendrix, are often synthesized using what type of reaction sequence involving two consecutive enolate alkylations

Chemistry
1 answer:
Alekssandra [3K]1 month ago
8 0

Answer:

Explanation:

Diethyl malonate possesses greater acidity compared to monocarbonyl substances (pKa=13) because its alpha hydrogens are linked to two carbonyl groups. Consequently, the malonic ester can be readily changed into its enolate ion by reacting it with sodium ethoxide in ethanol. When the malonic ester undergoes alkylation, a hydrogen atom in the alpha position becomes acidic, permitting another round of alkylation to yield a dialkylated malonic ester.

In this scenario, when diethyl malonate interacts with urea in the presence of sodium ethoxide base, the second alkylation step occurs within the molecule, producing a cyclic compound known as barbituric acid.

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What features of this model will help Armando answer the question?
lions [2927]

Answer:

The adjustable legs along with the sand table.

Note: The question is incomplete. The full question is presented below.

Using Models to Address Questions Regarding Systems

Armando’s class was examining images of rivers shaped by flowing water. Most rivers appeared wide and shallow, except for one, which was narrow and deep. The students theorized that this river's narrowness and depth are due to:

  • the steepness of the hill from which the water descends, or
  • the diminutive size of the sand grains the water flows through.

To explore the answer to the question of why this river is so narrow and deep, Armando created the model outlined below.

Explanation:

The model constructed by Armando will facilitate addressing the question due to specific features:

1. Adjustable leg - as one theory proposed by the class suggests that the steep hill affecting the water's path could be the reason for the river's dimensions, the adjustable legs are designed to be raised or lowered to alter the slope, allowing testing of this theory.

2. Sand table - this acts as the streambed. By modifying the size of the sand grains, students can examine the second hypothesis that smaller sand grains contribute to the river's narrowness and depth.

The outcomes of their experimentation will lead them to a conclusion.

5 0
1 month ago
Read 2 more answers
he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
eduard [2782]

1) Drift velocity: 3.32\cdot 10^{-4}m/s

2. 5.6\cdot 10^{13} electrons per individual

Explanation:

1)

In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:

v_d=\frac{I}{neA}

where

I stands for current

n represents the density of free electrons

e=1.6\cdot 10^{-19}C indicates the charge of an electron

A signifies the wire's cross-sectional area

The wire's cross-sectional area can be determined as

A=\pi r^2

where r denotes the wire's radius. Thus, the equation transforms to

v_d=\frac{I}{ne\pi r^2}

In this scenario, we have:

I = 8.0 A as the current

8.5\cdot 10^{28} m^{-3} indicates the free electron concentration

d = 1.5 mm is the diameter, making the radius

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

So, the resulting drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

2)

The entire length of the cord is

L = 3.00 m

And the cross-sectional area is

A=\pi r^2=\pi (0.75\cdot 10^{-3})^2=1.77\cdot 10^{-6} m^2

Consequently, the volume of the cord is

V=AL (1)

The number of electrons per unit volume is n, thus the total electrons in this cord would be

N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

Overall, the Earth's population rounds to 8 billion individuals, equating to

N'=8\cdot 10^9

Hence, the number of electrons distributed to each person is:

N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

7 0
1 month ago
PART A: Use the following glycolytic reaction to answer the question. If the concentration of DHAP is 0.125 M and the concentrat
alisha [2963]

Answer:

For A: The change in free energy for the reaction is -5339.76 J/mol

For B: Free energy change is expressed in kJ/mol

For C: The forward reaction favors progression, while the reverse reaction does not.

Explanation:

Regarding the specified chemical reaction:

DHAP\rightleftharpoons G_3P

  • For A:

The relationship between standard Gibbs free energy and equilibrium constant is as follows:

\Delta G^o=-RT\ln K_{eq}

The free energy change can be calculated using the following equation:

\Delta G=\Delta G^o+RT\ln Q

Or,

\Delta G=-RT^o\ln K_{eq}+RT\ln Q

where,

\Delta G = Change in free energy

R = Gas constant = 8.314J/K mol

T^o = standard temperature = 25^oC=[273+25]K=298K

T = temperature of the cell = 37^oC=[273+37]K=310K

K_[eq} = equilibrium constant = 5.4\times 10^{-2}

Q = reaction quotient = \frac{[G_3P]}{[DHAP]}

[G_3P] = 0.06 M

[DHAP] = 0.125 M

Substituting the values into the equation yields:

\Delta G=[-(8.314J/mol.K\times 298K\times \ln (5.4\times 10^{-2}))]+[(8.314J/mol.K\times 310K\times \ln (\frac{0.06}{0.125}))]\\\\\Delta G=-[-7231.46]+[-1891.7]=-5339.76J/mol

Thus, the change in free energy for the reaction is -5339.76 J/mol

  • For B:

To convert the free energy change to kilojoules, we apply the conversion factor:

1 kJ = 1000 J

So, -5339.76J/mol\times \frac{1kJ}{1000J}=-5.34kJ/mol

Consequently, the free energy change's units are kJ/mol

  • For C:

For spontaneity in the reaction, the Gibbs free energy must be negative. However, the calculations indicate a positive Gibbs free energy, leading to the conclusion that the reaction is not spontaneous.

The free energy change of the reaction is negative.

Consequently, the forward reaction is favored and the reverse reaction is not favored.

8 0
1 month ago
For which of the following reactions is ΔHrxn equal to ΔHf of the product? You do not need to look up any values to answer this
Alekssandra [3086]

Answer:

In all listed reactions, ΔH°rxn does not correspond to the ΔH°f of the resulting product.

Explanation:

The standard enthalpy of formation (ΔH°f) signifies the enthalpy change that occurs when 1 mole of a product is created from its basic elements in their standard states.

1/2 O₂(g) + H₂O(g) ⟶ H₂O₂(g)

ΔH°rxn does not equal ΔH°f of the product, since H₂O(g) is a compound rather than an element.

Na⁺(g) + F⁻(g) ⟶ NaF(s)

ΔH°rxn is not the same as ΔH°f of the product because Na and F are not in their standard states (Na(s); F₂(g)).

K(g) + 1/2 Cl₂(g) ⟶ KCl(s)

ΔH°rxn is not equal to ΔH°f of the product due to K being outside its standard state (K(s)).

O₂(g) + 2 N₂(g) ⟶ 2 N₂O(g)

ΔH°rxn does not match ΔH°f of the product as 2 moles of N₂O are produced.

In none of the above cases does ΔHrxn match ΔHf of the product.

7 0
22 days ago
Select all the element(s) from the periodic table shown that will form an ionic compound with a metal M and a nonmetal X and a f
VMariaS [2998]

Response:

Sulfate- SO4^2-

Sulfite- SO3^2-

Permanganate- MnO4

Carbonate- CO3^2

Clarification:

KEEP GOING WITH YOUR STUDIES!

4 0
1 month ago
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