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Roman55
1 month ago
14

(g) On the graph in part (d) , carefully draw a curve that shows the results of the second titration, in which the student titra

tes a 20.mL sample of 0.20MHCl(aq) with 0.10MNaOH(aq)
(h) ) The student made observations related to the contents of the Erlenmeyer flask during the titration. Identify an observation that could have led the student to conclude that a chemical change took place during the titration

Chemistry
1 answer:
Tems11 [2.7K]1 month ago
4 0

Response:

This is my understanding.

Explanation:

(g) Titration curves

While I can't create two curves on a single graph, I can depict them separately for clarity.

In part (d), the graph indicated an equivalence point at 20 mL.

For the second titration, since the NaOH concentration is doubled, the volume to reach the equivalence point will be halved — 10 mL.

Below are the two titration curves.

(h) Evidence of reaction

Both HCl and NaOH are colorless solutions.

There is no gas released or precipitate formed during their reaction.

It’s likely the student observed that the Erlenmeyer flask heated up, indicating a chemical change.

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How many molecules of PF5 are found in 39.5 grams of PF5?
Anarel [2989]

Response:

1.9 \times 10^{23} molecules of PF_5 can be found in 39.5 grams of PF_5.

Clarification:

Atomic weights: P= 31, F= 19,

The molar mass equals 1 atomic weight of P + 5 atomic weights of

 F= 31+5 × 19\times = 31+95

=126 g/mole

The number of moles in 39.5 gm of

equals \frac{Mass}{Molar mass}

 = \frac{39.5}{126}moles

 =0.3134 moles

1 mole of any substance encompasses

0.3131 moles comprises 0.3134

= 1.9 \times 10^{23} molecules

Thus, 1.9 \times 10^{23} molecules of PF_5 can be found in 39.5 grams of PF_5.

7 0
4 days ago
Draw the structures of two different compounds that have the composition CH3NO2. All three H atoms must remain bonded to the C a
Tems11 [2777]

Answer:

The configurations are illustrated below.

Explanation:

Hydrogen possesses a single electron in its outer shell, carbon has 4, nitrogen has 5, and oxygen holds 6. To achieve an octet (or duet for hydrogen), they require 1, 4, 3, and 2 electrons respectively.

Therefore, each hydrogen atom will share one electron with carbon, while the remaining electron will be shared with nitrogen, maintaining 4 electrons available for sharing. Carbon can form two bonds with both oxygen atoms, expanding its octet; however, this renders it unstable, leading to the formation of resonance structures (redistribution of electrons), and charge formation. One of the oxygen atoms will share only one electron with nitrogen.

The two structures are depicted below.

3 0
21 day ago
A certain liquid has a density of 2.67 g/ cm3. what is the mass of 30.5 ml of this liquid? (
lorasvet [2795]
Hello!

density = 2.67 g/cm³

volume = 30.5 mL

Thus:

Mass = density * volume

Mass = 2.67 * 30.5

Mass = 81.435 g 
4 0
1 month ago
What is the symbol for the isotope of 58 co that possesses 33 neutrons?
KiRa [2933]
The element with atomic number 58 is Cerium, meaning its symbol should be Ce rather than Co, which belongs to Cobalt with atomic number 27. Therefore, the notation for isotopes consists of the element's symbol accompanied by a superscript and a subscript, properly aligned. The superscript indicates the mass number.

Mass number = protons + neutrons = 58 + 33 = 91

The subscript denotes the atomic number, which is 58. This notation is illustrated in the attached image.

6 0
1 month ago
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Methane (CH4, 16.05 g/mol) reacts with oxygen to form carbon dioxide (CO2, 44.01 g/mol) and water (H2O, 18.02 g/mol). Assume tha
lorasvet [2795]
The percent yield is calculated as 54.5.
4 0
8 days ago
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