A boy climbs to the top of a tree and sees his friend 100 feet from the base of the tree. If the tree is 25 feet tall, what is t

Respuesta:

Explicación paso a paso:

V=1/2lbh

V=1/2×15×8×6

V=360pulgadas

Response:

To accumulate $7,500 in three years, the required one-time deposit is $4388.17

Step-by-step explanation:

Basic Financial Formulas

A commonly used formula for calculating present and future values is

Where FV represents the future value, PV denotes the present value, r signifies the interest rate, and n indicates the number of compounding periods. It’s essential to remember that r and n must correspond to the same compounding duration, e.g. r is compounded monthly while n is expressed in months.

The inquiry seeks to determine the PV necessary as a one-time deposit to achieve a future value of $7,500 in 3 years at an interest rate of 1.5% compounded monthly.

FV=7,500

r=1.5%=0.015

n=3*12=36 months

We have changed n to months since r is monthly compounded. The equation

must be arranged to isolate PV.

Response

Response:

The coach should begin seeking players who weigh at least 269.55 pounds.

Step-by-step explanation:

We have these details from the question:

Average, μ = 225 pounds

Standard Deviation, σ = 43 pounds

The weights follow a bell curve, indicating a normal distribution.

Formula:

We need to establish the value of x that corresponds to a probability of 0.15

Review from the standard normal z table gives us:

Consequently, the coach should start recruiting players weighing at least 269.55 pounds.

To plot the graph of a linear equation, two points suffice to create a line.

Nevertheless, errors can occur; thus, when the line is drawn, it may seem accurate. Two points will always define a line, regardless of the correctness of those points.

To confirm that the points are accurate, we find a third point to verify that the two previously calculated points are correct and that all points align on the same line. If they don’t, an error has been made.

Option A) is the correct choice

Response:

0.14 s

Detailed breakdown:

s = -2.7 t² + 40t + 6.5

Set s = 12

12 = -2.7t² + 40t + 6.5     Rearranging yields

-2.7t² + 40t + 6.5 - 12 = 0

      -2.7t² + 40t - 5.5 = 0

Utilize the quadratic formula

a = -2.7; b = 40; c = -5.5

x = 7.41 ± 7.27

x₁ = 0.14; x₂ = 14.68

The graph indicates roots at x₁ = 0.134 and x₂ = 14.68.

The surface of the Moon stands at -12 ft. Thus, the ball will reach a height of 12 ft above the Moon’s surface (crossing the x-axis) at 0.14 s.

The second root indicates when the ball is again 12 ft above the lunar surface as it descends.