If 300. mL of water are poured into the measuring cup, the volume reading is 10.1 oz . This indicates that 300. mL and 10.1 oz a
2 answers:
Answer: 29.7 mL is equivalent to a fluid ounce according to this information.
Explanation:
It is given that 300 mL is equal to 10.1 oz, which indicates that,
300 mL = 10.1 oz
or,
10.1 oz = 300 mL
Now, we need to ascertain the volume in milliliters for one fluid ounce.
Since 10.1 oz of fluid equals 300 mL,
This means 1 oz of fluid =
= 29.7 mL
Thus, based on this data, 29.7 mL are contained in one fluid ounce.
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Response:
The speed at which the distance from the helicopter to you is changing (in ft/s) after 5 seconds is ft/ sec
Clarification:
Provided:
h(t) = 25 ft/sec
x(t) = 10 ft/ sec
h(5) = 25 ft/sec. 5 = 125 ft
x(5) = 10 ft/sec. 5 = 50 ft
At this point, we can determine the distance between the individual and the helicopter utilizing the Pythagorean theorem
Now, let's calculate the derivative of distance in relation to time
By plugging in the values for h(t) and x(t) and simplifying, we arrive at,
=
=
ft / sec
Answer:
130 m/s (to two significant figures)
Explanation:
In projectile motion, the launching velocity and launch angle help to determine both the horizontal and vertical velocity components.
u represents the initial projectile velocity = 150 m/s
uₓ = u cos θ = 150 cos 30° = 129.9 m/s
uᵧ = u sin θ = 150 sin 30° = 75.0 m/s
A projectile's motion can be viewed as made up of independent vertical and horizontal elements.
The vertical motion is affected by gravitational acceleration (which pulls down on the projectile), altering the vertical velocity component due to this acting force.
Conversely, there is no acting force in the horizontal direction, which means the horizontal component maintains a steady velocity throughout the projectile's flight.
Thus, at t = 4 s, the horizontal component of the projectile's speed remains equal to the initial horizontal velocity component.
At t = 4 s, the horizontal component of velocity is uₓ = u cos θ = 150 cos 30° = 129.9 m/s ≈ 130 m/s
