answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eddi Din
8 days ago
7

You are stranded on a deserted island with 100 m of 18 gauge insulated copper wire, a light bulb rated at 3.0 V, a 50 V battery,

a large iron nail, a few simple tools (including wire cutters), and your clothes. There are of course trees, rocks, sand, and other assorted island flora and fauna. (The island is a bit unique: there is a dampening field present that inhibits fire.) Since you have been stranded on the island, each night after dark a helicopter flies over.
Using the materials at hand, describe a way to get yourself rescued. (You must support your description by including brief references to any laws or equations that apply.)
Physics
2 answers:
Keith_Richards [3.2K]8 days ago
7 0

Respuesta:Se puede obtener rescate enviando señales de SOS tanto de día como de noche como se explica a continuación

Justificación:

Para responder a la pregunta, notamos que

Durante el día

Dado que tenemos arena y rocas, podemos inscribir SOS en la arena

También podemos usar las rocas para construir tres marcas de X en un patrón triangular señalando SOS

De noche

1. Crear una luz intermitente para atraer al helicóptero

Para eso, podemos envolver el cable de cobre en una bobina, conectarlo a la bombilla de 3.0 V y a la batería de 50 V

La corriente a través de la bobina disminuye y aumenta a medida que el clavo de hierro se desliza dentro y fuera de la bobina, haciendo que la luz se atenúe y brille, de modo que intermitente.

La ecuación para la corriente a través de la bobina se da de la siguiente manera;

Current, \ I = \frac{Voltage}{Impedance}

Donde:

Impedancia = \bar Z = R +j·X

El valor de X varía a medida que el clavo se mueve en la bobina.

2. Señal SOS

La señal SOS también puede hacerse directamente encendiendo y apagando la bombilla usando tres destellos cortos seguidos de tres destellos largos y luego tres destellos cortos, que se pueden lograr completando y desconectando la bombilla eléctrica, el cable de cobre y la batería de 50 V directamente como se ha descrito o cubriendo la bombilla encendida constantemente con la ropa de forma secuencial.

Maru [3.3K]8 days ago
6 0

Explicación:

Dado que la persona tiene un cable de cobre, enciende la bombilla y una batería. Para mostrar su marca durante la noche, encendería la bombilla.

Para eso, haría dos cables. Conectar un cable con el extremo negativo de la batería y conectar el otro extremo del cable con la base de la bombilla. Conectar el otro cable al extremo positivo de la batería y a la base de la bombilla. Esto completaría el circuito para encender la bombilla.

Ahora, dado que la batería también necesita ser cargada, utilizará el cable de cobre y un clavo de hierro. Cuando mueva el clavo de hierro rápidamente a través de una bobina de cable de cobre, se producirá electricidad que se usará para cargar la batería.

You might be interested in
Consider the uniform electric field E = (2.5 j + 3.5 k) × 103 N/C. (a) Calculate the electric flux through a circular area of ra
kicyunya [3294]
The desired electric flux Φ is calculated from the electric field E=(2.5• j + 3.5• k) ×10³ N/C and a circular path with a radius r=2.5m. The electric flux across a surface is represented as Φ=∮E•dA. Given the area A lies in the yz-plane, the normal orientation flows in the x-direction with A=πr² leading to dA=2πrdr •i. Thus, Φ evolves to Φ=∮(2.5j + 3.5k)×10³•(2πrdr i). Integrating from r=0 to r=2.5m and noting that components in different directions yield zero, results in Φ equaling 0 Nm²/C. Regarding the second part, when the area vector is at a 45° angle to the xy-plane, we redefine dA as (2πrCos45 i + 2πrSin45 j) dr, leading to the new flux calculation as Φ=10³∮ 5πrSin45 dr, integrating from 0 to 2.5m. With substitutions made, the result comes to Φ=34.71×10³ Nm²/C.
3 0
1 month ago
Planting of crops to purify -lucern, shrubs, trees(possible job creation)
kicyunya [3294]
These plants were utilized to eliminate harmful substances from the environment. In today's world, such crops have evolved into a significant asset and can be a source of profit when managed properly, creating multiple job opportunities along the way. Hope this information is useful.
8 0
20 days ago
Read 2 more answers
Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat
Yuliya22 [3333]

Answer:

Explanation:

The distance between the electrodes is denoted as d.

The kinetic energy of the electron is represented as Ek when the electrodes are positioned at a distance of "d" apart.

Our goal is to determine the kinetic energy when they are separated by a distance of d/3.

K.E = ½mv²

It’s important to note that the mass remains constant; only velocity varies.

Additionally,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Assuming constant acceleration

Hence, m and a are fixed,

therefore,

K.E is directly related to d

Thus, as d increases, K.E increases, and conversely, when d decreases, K.E decreases.

Consequently,

K.E_1 / d_1 = K.E_2 / d_2

With K.E_1 equating to E_k

and d_1 being d

while d_2 is represented as d/3

This leads to K.E_2 = K.E_1 / d_1 × d_2

Thus, K.E_2 = E_k × ⅓d / d

Finally,

K.E_2 = ⅓E_k

Therefore, the resultant kinetic energy is one third of the original E_k

7 0
16 days ago
Which characteristics of Earth’s orbit are in agreement with Kepler’s second law? Check all that apply.
Maru [3345]

Here is an image displaying the correct answers.

6 0
1 month ago
Read 2 more answers
Sketch a position-time graph for a bear starting
Sav [3153]
Hopefully this clarifies things. The position remains unchanged over the span of 5 seconds, which indicates that it is at rest while time continues to pass. When the slope turns negative, it illustrates that the bear is moving backward, thus changing its direction.
3 0
10 days ago
Other questions:
  • hows a map of Olivia's trip to a coffee shop. She gets on her bike at Loomis and then rides south 0.9mi to Broadway. She turns e
    10·1 answer
  • Over a period of more than 30 years, albert klein of california drove 2.5 × 106 km in one automobile. consider two charges, q1 =
    5·1 answer
  • The density of aluminum is 2.7 × 103 kg/m3 . the speed of longitudinal waves in an aluminum rod is measured to be 5.1 × 103 m/s.
    15·1 answer
  • Suppose a rectangular piece of aluminum has a length D, and its square cross section has the dimensions W XW, where D (W x W) to
    11·1 answer
  • You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball
    10·1 answer
  • A venturi is constructed of a 10.0 cm pipe with a 2.0 cm diameter throat. Water pressure in the pipe is twice atmospheric pressu
    12·1 answer
  • A wind turbine with a rotor diameter of 40 m produces 90 kW of electrical power when the wind speed is 8 m/s. The density of air
    14·1 answer
  • You read that light waves travel through air and water at different speeds. What is one way this can affect what you see around
    11·1 answer
  • A player throws a football 50.0 m at 61.0° north of west. what is the westward component of the displacement of the football?
    15·1 answer
  • An 8.0-kg history textbook is placed on a 1.25-m high desk. How large is the gravitational potential energy of the textbook-Eart
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!