We cannot infer that the proportion of wives married less than two years intending to have children is significantly greater than that of those married for five years.
To find the maximum number of identical packs we see we have 72 pencils and 24 calculators.
This involves discovering the largest number that divides both 72 and 24 evenly,
which is known as the GCM or greatest common multiplier.
To determine the GCM, factor 72 into primes and group them:
72=2 times 2 times 2 times 3 times 3
24=2 times 2 times 2 times 3
Thus, the common grouping is 2 times 2 times 2 times 3, equating to 24.
Therefore, the maximum number of packs is 24.
For pencils:
72 divided by 24=3
Resulting in 3 pencils per pack.
For calculators:
24 divided by 24=1
So, 1 calculator per pack.
The outcome is 3 pencils and 1 calculator in each pack.
Try this method:
When a graph shifts right, replace 'x' with 'x' minus the number.
When it shifts down, subtract the number from 'y'.
So the final equation becomes: y = 4(x - 5)² - 18.
The answer is A.
P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'
Answer:
UB: 375
Step-by-step explanation:
370mm rounded to 2 significant figures is..
UB: 375
LB:365
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