To address this issue, we will utilize the principles concerning the calculation of significant figures while considering tolerance levels. Additionally, we must ensure that the total significant digits in the final result does not exceed those of the given values:
PART A) The thickness of the collection of 52 cards is
The thickness, t, of a single card can be:
For the 52 cards, the thickness has 3 significant figures and the associated uncertainty has 1 significant digit. Therefore,
the significant figures for one card's thickness and the uncertainty must also align at 3 and 1 respectively.
Thus, the thickness of an individual card is
PART B) The uncertainty for one card when measured using a single deck is 0.0001 inch.
The number of decks, n, needed to achieve an uncertainty of 0.00002 inch is
Consequently, 5 decks are necessary to measure the thickness of a single card with a 0.00002 inch uncertainty.
Answer:
Explanation:
a) La fuerza neta que actúa sobre la caja en la dirección vertical es:
Fnet=Fg−f−Fp *sin45 °
aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.
Fnet=ma
ma=Fg−f−Fp *sin45 °
a=
=0.24 m/s²
Vf =Vi +at
=0.48+0.24*2
Vf=2.98 m/s
b)
Fnet=Fg−f−Fp *sin45 °
=Fg−0.516Fp−Fp *sin45 °
=30-1.273Fp
Fnet=0 (Ya que la velocidad es constante)
Fp=30/1.273
=23.56 N
Answer:
A = 4.76 x 10⁻⁴ m²
Explanation:
Given data:
Person's weight = 625 N
Bike's weight = 98 N
Pressure per tire = 7.60 x 10⁵ Pa
Find: Contact area per tire
Total system weight = 625 + 98 = 723 N
Let F represent the force supported by each tire
2F = 723 N
Therefore, F = 361.5 N
Using the formula F = P × A
Contact area, A = 4.76 x 10⁻⁴ m²
Answer:900 feet
Explanation:
Given
Velocity
It takes 100 feet to come to a stop.
Utilizing the equation of motion
Where
v,u=Final and initial velocities
a=acceleration
s=distance traveled
When the speed is 60 mph
s=900.08 feet