Answer:
1. The speed of the Volvo is 27.3 m/s
2. The speed of the Alpha Romeo is 10.8 m/s
Explanation:
1. Parameters given:
v = the speed of the Volvo
m₁ = the mass of the Volvo
v₁ = the speed of the Volvo prior to collision
Distance during skidding = 30 m
Where a denotes deceleration = -2.94 m/s²
To solve for v
Following the collision, both cars travel as one, thus
The momentum conservation in the X direction is then:
2. The momentum conservation in the Y direction gives:
Answer
Data provided:
mass of the block = 200 g = 0.2 Kg
Velocity at A = 0 m/s
Velocity at B = 8 m/s
distance of slide = 10 m
height of the block = 4 m
calculation for the block's potential energy
P = m g h
P = 0.2 x 9.8 x 4
P = 7.84 J
kinetic energy calculated as
Work done = P - KE
work = 7.84 - 6.14
work = 1.7 J
b) using the formula v² = u² + 2 a s
0 = 8² - 2 x a x 10
a = 3.2 m/s²
ma - μ mg = 0
To tackle this issue, we will utilize concepts related to gravity based on Newtonian definitions. To find this value, we'll apply linear motion kinematic equations to determine the required time. Our parameters include:
Comet mass
Radius
The rock is released from a height 'h' of 1 m above the surface.
The relationship for gravity's acceleration concerning a body with mass 'm' and radius 'r' is described by:
Where G represents the gravitational constant and M denotes the mass of the planet.
Now, let’s compute the time value.
Ultimately, the time for the rock to hit the surface is t = 87.58s.
Answer:
a) ∆x∆v = 5.78*10^-5
∆v = 1157.08 m/s
b) 4.32*10^{-11}
Explanation:
This problem can be addressed using Heisenberg's uncertainty principle, which is expressed as:
Where h represents Planck’s constant (6.62*10^-34 J s).
Assuming that the electron's mass remains the same, we proceed as follows:
Utilizing the electron's mass (9.61*10^-31 kg) and the uncertainty in position (50 nm), we can compute ∆x∆v and ∆v:
If we treat the electron like a classic particle, the time required to cross the channel is determined using the upper limit of the uncertainty in velocity: