A basketball player maintains a steady pace of 2.5 m/s while throwing a basketball vertically at 6.0 m/s. How far does the player advance before getting the ball back? Air resistance is negligible. I was unsure which formula to apply to this scenario. Is there any relevance to an angle? First, we determine the duration to reach peak height. The total time for the flight will be double the ascent duration. According to Newton's equations of motion: v = u + at. At the highest point, v = 0, where u is 6 m/s. Thus, the equation becomes 0 = 6 - 9.81t, leading us to t = 0.61 seconds. Therefore, the total flight time equals 1.22 seconds as the player runs towards the ball at a horizontal speed of 2.5 m/s. The distance traveled can be calculated using distance = speed × time, resulting in distance = 2.5 m/s * 1.22, yielding a final distance of 6.11m.
Definamos h como la distancia que hay desde el borde del pozo hasta la superficie del agua (en metros).
Consideremos la gravedad g como 9.8 m/s² y despreciemos la resistencia del aire.
La velocidad inicial vertical del guijarro es nula.
Ya que el guijarro impacta el agua tras 1.5 segundos, entonces:
h = 0.5 * (9.8 m/s²) * (1.5 s)² = 11.025 m
Resultado: 11.025 m
2 minutes = 120 seconds
120/15 = 8
The black horse corresponds to 8 seconds.
Response: a) 0.04 kW = 40 W
b) 0.05
Explanation:
A)
The thermal efficiency of the power cycle is calculated as Input / Output
Input = 10 kW + 14,400 kJ/min which translates to 10 kW + 14,400 kJ/(60s) = 10 kW + 14,400/60 kW.
Output equals 10 kW
Thus, Thermal Efficiency = Output / Input = 10 kW / 250 kW = 0.04 kW = 40 W
B)
Maximum Thermal Efficiency of the power cycle is defined as 1 - T1/T2
where T1 = 285 Kelvin
and T2 = 300 Kelvin
Thus, Maximum Thermal Efficiency = 1 - T1/T2 = 1 - 285/300 = 0.05
For a string that is secured at both ends, the oscillation amplitude must be zero at both extremities of the string. Refer to the attached images for clarity. It is evident that our fundamental harmonic will have the following wavelength: All subsequent harmonics are simply multiples of the fundamental. The three longest wavelengths are as follows:
