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Slav-nsk
1 month ago
10

20 boxes of apples have been delivered to a restaurant. The number of apples in each box is counted. Complete the table below an

d answer the following question. What is the mean number of apples in a box?

Mathematics
1 answer:
Leona [12.3K]1 month ago
3 0

Answer:

30 apples

Step-by-step explanation:

The cumulative total of apples is 600 (summing all figures in the apples*frequency column). Dividing this total by 20 boxes provides an average of 30 apples per box.

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How to round 47,125 to the nearest ten,to the nearest hundred, to the nearest thousand and to the nearest ten thousand
zzz [12059]
To round the figure 47,125 to the closest tenth, hundredth, and thousandth, it's essential to recognize the positions of these places. The tens position is the second digit from the right. The hundreds position is the third, and the thousands position is the digit immediately following the comma. For rounding to the tens place, you must inspect the digit directly behind it (the ones place) and evaluate. If this digit is between 0-4, you won’t round the tens place, but if it falls between 5-9, rounding is permissible. The same regulation applies when rounding up for the hundreds and thousands places. Consequently, the number arrived at is - 47,135. 
8 0
1 month ago
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The graph of f(x) = 2x is shown on the grid. The graph of g(x) = ()x is the graph of f(x) = 2x reflected over the y-axis. Which
zzz [12059]

Response:

The graph in question is linked to g(x) = -2x, though it is not provided.

Detailed explanation:

A reflection across the y-axis changes the sign of the x-coordinate for every point. To derive the new function, we substitute x with -x:

g(x) = f(-x) = 2(-x) = -2x

This leads us to g(x) = -2x.

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1 month ago
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The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
PIT_PIT [12108]

Answer:

The tangent plane equation for the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

We have

The ellipsoid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation for the tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  (Given)

The hyperboloid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The tangent plane equation at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The tangent plane equation for the hyperboloid is

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The tangent plane equation

2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2

Hence, the required tangent plane equation for the hyperboloid is

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

7 0
1 month ago
The figure shows the design of a greenhouse with a rectangular floor. The front and back sides of the greenhouse are semicircles
tester [12085]

9514 1404 393

Answer:

96 cubic feet

Step-by-step explanation:

The volume calculation for the dimensions of 16 ft by 18 ft by 1/3 ft is as follows:

V = LWH

V = (16 ft)(18 ft)(1/3 ft) = 96 ft³

Thus, 96 cubic feet of concrete will be required.

7 0
1 month ago
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [12059]
\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
1 month ago
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