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aliya0001
4 days ago
15

Two conducting spheres, one having twice the diameter of the other, are separated by a distance that is large compared to their

diameters. The smaller sphere has charge q and the larger sphere is uncharged. If the spheres are connected by a long, thin wire, then after a sufficiently long time:
a.The two spheres are at the same potential.
b. The electric field at the surface of the two spheres has the same magnitude.
c. The two spheres have the same charge.
d.The larger sphere is at twice the potential of the smaller sphere.
e.The smaller sphere is at twice the potential of the larger sphere.
Physics
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A 40-kg uniform semicircular sign 1.6 m in diameter is supported by two wires as shown. What
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The findings indicate T1 = 131.4 [N] and T2 = 261 [N].
4 0
1 month ago
An object experiences an acceleration of -6.8 m/s​2.​ As a result, it accelerates from 54 m/s to a complete stop. How much dista
Maru [3345]
The distance covered during the acceleration phase is d = 214.38 m. Given parameters include the acceleration of the object, a = -6.8 m/s², initial speed, u = 54 m/s, and final speed, v = 0. The equation for acceleration is defined as a = (v - u) / t. Therefore, rearranging gives t = (v - u) / a, resulting in t = (0 - 54) / (-6.8) = 7.94 s. The average speed of the object is V = (54 + 0)/2 = 27 m/s. The displacement is calculated as d = V x t = 27 x 7.94 = 214.38 m. Thus, the total distance traveled during that period of acceleration is 214.38 m.
3 0
1 month ago
Find the lengths of each of the following vectors
serg [3582]

Answer:

Explanation:

The length of a vector refers to its magnitude.

For a vector

R = a•i + b•j + c•k

The magnitude can be calculated using

|R|= √(a²+b²+c²)

Applying this formula to each given vector yields the following results.

(a) 2i + 4j + 3k

The length is

L = √(2²+4²+3²)

L = √(4+16+9)

L = √29

L = 5.385 unit

(b) 5i − 2j + k

Note that k represents 1k

The length is

L = √(5²+(-2)²+1²)

Because, -×- = +

L = √(25+4+1)

L = √30

L = 5.477 unit

(c) 2i − k

As there is no j component, it means that the j component is 0

L = 2i + 0j - 1k

The length is

L = √(2²+0²+(-1)²)

L = √(4+0+1)

L = √5

L = 2.236 unit

(d) 5i

Similarly, without a j-component and k-component

L = 5i + 0j + 0k

The length is

L = √(5²+0²+0²)

L = √(25+0+0)

L = √25

L = 5 unit

(e) 3i − 2j − k

The length is

L = √(3²+(-2)²+(-1)²)

L = √(9+4+1)

L = √14

L = 3.742 unit

(f) i + j + k

The length is

L = √(1²+1²+1²)

L = √(1+1+1)

L = √3

L = 1.7321 unit

3 0
2 months ago
a fixed mass of a n ideal gas is heated from 50 to 80C at a constant pressure at 1 atm and again at a constant pressure of 3 atm
inna [3103]

Answer:

The required energy remains identical in both scenarios since the specific heat capacity (Cp) does not change with varying pressure.

Explanation:

Given;

initial temperature, t₁ = 50 °C

final temperature, t₂ = 80 °C

Temperature change, ΔT = 80 °C - 50 °C = 30 °C

Pressure for scenario one = 1 atm

Pressure for scenario two = 3 atm

The energy needed in both scenarios is expressed as;

Q = M*C_p*\delta T

Where;

Cp denotes specific heat capacity, which only varies with temperature and remains unaffected by pressure.

Hence, the energy required remains the same for both scenarios since specific heat capacity (Cp) is pressure-independent.

8 0
2 months ago
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