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Digiron
8 days ago
6

A 15-kg block at rest on a horizontal frictionless surface is attached to a very light ideal spring of force constant 450 N/m. T

he other end of the spring is attached to a fixed wall. A lump of putty travels horizontally with a speed of 8.0 m/s towards the block from the side directly opposite the spring. The putty strikes and sticks to the block. What is the maximum distance the spring is compressed after the impact
Physics
1 answer:
Maru [2.3K]8 days ago
7 0
μk = (d1)sin(θ) / [(cosθ)(d1) + (d2)]. In this situation, we apply the work/energy principle which asserts that the change in kinetic energy equals the total work exerted on the system by all forces. Given the object is at rest initially and finally, the change in kinetic energy (ΔKE) is zero, indicating total work done must coincide with this state.
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Jo, Daniel and Helen are pulling a metal ring. Jo pulls with a force of 100N in one direction and Daniel with a force of 140N in
inna [2205]

Answer:

She exerts a force of 40 N.

Explanation:

The fact that the ring remains stationary indicates that the forces are in equilibrium.

Let’s denote Jo's force as x.

The equation to consider is

140 = x + 100

x = 40

5 0
14 days ago
If a 50.0-kg mass weighs 554 n on the planet saturn, calculate saturn’s radius
ValentinkaMS [2425]

Answer:

17.35 × 10^(-6) m

Explanation:

Mass; m = 50 kg

Weight; W = 554 N

From the formula:

W = mg

This simplifies to; 554 = 50g

g = 554/50

g = 11.08 m/s²

Also, using the formula;

mg = GMm/r²

hence; g = GM/r²

Rearranging gives;

r = √(GM/g)

With G as a known constant of 6.67 × 10^(-11) Nm²/kg²

r = √(6.67 × 10^(-11) × 50/11.08)

r = 17.35 × 10^(-6) m

8 0
22 days ago
Starting with only the Balmer series light (visible light), how could we ensure that the solar panels generate a current that Ma
ValentinkaMS [2425]

The right answer is (a).

Solar panels create electric current through the photoelectric effect, which describes how photons strike certain material surfaces, resulting in the release of electrons when light with the correct frequency hits them. A photon will interact with an electron on the panel, causing it to be ejected from the panel's surface.

As the illumination on the panel becomes brighter, the intensity of the light rises, indicating an increase in the number of photons. Each photon has the potential to liberate an electron; thus, as the number of incoming photons rises, so does the quantity of freed electrons. Given that the photoelectric current reflects the rate at which these electrons flow, an increase in light intensity leads to a corresponding rise in the photoelectric current.

If the frequency of the light is increased without a change in brightness, the photoelectric current remains the same because the total number of photons does not increase. Yet, the electrons that are ejected do escape with higher kinetic energy. However, since the total number of electrons liberated stays unchanged, the current remains constant regardless of the electrons' increased energy. Thus, option b is incorrect.

Increasing the wavelength of the light means the energy of the photons decreases. This would cause the emitted electrons to have lower energy. However, if the brightness is consistent, the number of electrons remains the same, and as a result, there would be no change in the photoelectric current. Therefore, choice (c) is also incorrect.

The correct answer is (a). To generate the needed current, the brightness of the incident light must be increased.

8 0
26 days ago
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Problem: An ice hockey player hits a puck of mass 0.15 kilograms with a force of 100 newtons in the horizontal direction. What i
ValentinkaMS [2425]
The acceleration of an object will always align with the direction of the resultant force acting upon it. Thus, we can find horizontal acceleration by examining the horizontal force applied, applying Newton's second law in its mathematical form: Force = mass * acceleration. Therefore, acceleration = force / mass. By inputting the numbers, we have a = 100 / 0.15, which results in a = 666.7 m/s². Consequently, the acceleration experienced by the hockey puck is 670 m/s².
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5 days ago
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