A tank holds 17 3/5 gallons after losing 36 2/3 gallons, 4 5/6 gallons,and 27 1/12 gallons in 3

A rectangular garden is 6 feet long and 4 feet wide. A second rectangular garden has dimensions that are double the dimensions o

Svet_ta [12734]

Response:

100 percent increase

Detailed explanation:

1st garden

Length = 6 ft

Width = 4 ft

Perimeter = 2 (l+w)

= 2 (6+4) = 2(10) = 20

2nd garden

The length and width of this garden are double those of the first

Length = 2 *6 = 12

Width = 2 *4 = 8

Perimeter = 2 (l+w)

= 2 (12+8) = 2(20) = 40

Percent change = (new - old )/old * 100 percent

The first garden represents the old garden = 20 and the second refers to the new garden = 40

Substituting values in

Percent change = (40-20)/20 = 20/20 =100 *100 percent

= 100 percent increase

5 0

1 month ago

The community college fine arts department sold three kinds of tickets to its latest dance presentation. The adult tickets sold

babunello [11817]

Adult tickets sold = 75, Students = 200, Children = 75. To find the values, we use the variables for adult tickets, students, and children and set a series of equations based on the total tickets sold and both the pricing and quantity, leading to a solution of ticket counts.

8 0

1 month ago

Read 2 more answers

The parent cosecant function is shifted 4 units right and 3 units up. Which of the following is the graph of the transformed fun

AnnZ [12381]

We can use a graphing tool to plot the <span> cosecant function
</span>check the attached image

the answer corresponds to option B

4 0

2 months ago

Read 2 more answers

At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

Zina [12379]

Answer:

(a1) The chance that the temperature rises by less than 20°C is 0.667.

(a2) The probability of the temperature increase falling between 20°C and 22°C is 0.133.

(b) The likelihood that the temperature increase could be hazardous at any moment is 0.467.

(c) The anticipated value of the temperature rise is 17.5°C.

Step-by-step explanation:

Let X denote the temperature increase.

The random variable X is distributed uniformly over the interval [10°C, 25°C].

The probability density function for X is shown here:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

The probability of the temperature increase being under 20°C can be calculated as follows:

$P(X$

Consequently, the chance that the temperature increase will be below 20°C is 0.667.

(a2)

The probability of the temperature rise being in the range from 20°C to 22°C is computed as follows:

$P(20$

This leads to the probability of the temperature increase being between 20°C and 22°C being 0.133.

(b)

To find the probability that the increase in temperature could be dangerous, we calculate:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$

This results in a probability of 0.467 that the temperature rise is potentially dangerous at any time.

(c)

The expected value of the uniform random variable X is determined as follows:

$E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5$

The expected value for the temperature increase computes to 17.5°C.

7 0

2 months ago