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timurjin
1 month ago
10

If ef bisects angle ceb,angle cef=7x+31 and angle feb=10x-3

Mathematics
1 answer:
lawyer [9.2K]1 month ago
7 0

Given: The angle < CEB is divided by EF.

< CEF = 7x +31.

< FEB = 10x -3.

We will find the values of x and the measures of < FEB, < CEF, and < CEB.

Solution: The angle < CEB is divided into two angles < FEB and < CEF.

Therefore,   < FEB is equal to < CEF.

By substituting the values of < FEB and < CEF, we obtain:

10x -3 = 7x +31

By adding 3 to both sides, we have:

10x -3 +3 = 7x +31 +3.

Thus, 10x = 7x + 34

After subtracting 7x from both sides, we conclude:

10x -7x = 0 + 34.

This simplifies to 3x = 34.

Dividing both sides by 3 yields:

x = 11.33.

Substituting x=11.33 into < CEF = 7x +31 gives us:

< CEF = 7(11.33) +31 = 79.33 +31 = 110.33.

< FEB  = < CEF =  110.33 (approximately)

< CEB = < FEB +  < CEF  = 110.33 +110.33 = 220.66 (approximately)



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