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Wewaii
2 days ago
11

Which expressions can be used to find m∠BAC? Select three options. cos−1(StartFraction 6.9 Over 12 EndFraction) cos−1(StartFract

ion 9.8 Over 12 EndFraction) sin−1(StartFraction 6.9 Over 12 EndFraction) sin−1(StartFraction 9.8 Over 12 EndFraction) tan−1(StartFraction 6.9 Over 9.8 EndFraction)
Mathematics
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Consider this system of equations. Which shows the second equation written in slope-intercept form? y = 3 x minus 2. 10 (x + thr
Leona [12618]

Question

Consider this system of equations. Which shows the second equation written in slope-intercept form?

y = 3x - 2.

10(x + \frac{3}{5} ) = 2y

A. y = 5x + \frac{3}{10}

B. y = 5x + 3

C. y = \frac{1}{5} x + \frac{3}{25}

D. y = \frac{1}{2} x + 6

Response:

B. y = 5x + 3

Detailed explanation:

Given

Equation 1: y = 3x - 2.

Equation 2: 10(x + \frac{3}{5} ) = 2y

Required:

Equivalent of equation 2

To achieve an equivalence of equation 2 (in slope-intercept form), we must first simplify it

10(x + \frac{3}{5} ) = 2y

Open the brackets

10*x + 10 *\frac{3}{5} = 2y

10x + \frac{30}{5} = 2y

Simplify the fractions

10x + 6 = 2y

Divide by 2

\frac{10x}{2} + \frac{6}{2} = \frac{2y}{2}

5x + 3 = y

Re-arrange

y = 5x + 3

Next, we compare options A through D with y = 5x + 3

A. is not equal to y = 5x + 3

Next, we check the second option

B.

y = 5x + 3 matches y = 5x + 3

This option represents the second equation in slope-intercept format.

We check for further options

C.

y = \frac{1}{5} x + \frac{3}{25}

Convert the fraction into a decimal

y = 0.2x + 0.12

This does not equal y = 5x + 3

D.

y = \frac{1}{2} x + 6

Convert the fraction to decimal

y = 0.5x + 6

This also does not equal to y = 5x + 3

Therefore, the only option equivalent to the second equation in slope-intercept form is Option B

7 0
1 month ago
Read 2 more answers
A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
babunello [11817]
The P-value to evaluate the claim that the mean length of pencils produced in this factory equals 18.0 cm is 0.00736. Step-by-step explanation: In this case, a quality control specialist extracted a random sample of 45 pencils from the assembly line, which exhibited a mean length of 17.9 cm. With a known population standard deviation of 0.25 cm, we denote by the population mean length for pencils produced in the factory. Thus, Null Hypothesis: = 18.0 cm (indicating that the population mean length equals 18.0 cm). Alternate Hypothesis: ≠ 18.0 cm (suggesting different from 18.0 cm). We apply the one-sample z-test since the population standard deviation is known. The test statistic yields: T.S. ~ N(0,1), with the sample mean length 17.9 cm and population standard deviation 0.25 cm for a sample size of 45. Hence, the calculated test statistic is -2.68. The corresponding P-value is derived from P(Z < -2.68) = 1 - P(Z > 2.68), equating to 1- 0.99632 = 0.00368. For a two-tailed test, the resulting P-value computes to 2 * 0.00368 = 0.00736.
7 0
1 month ago
A box with rectangular sides has width twice the length of the base. The volume is 24 cubic inches and the total surface area of
lawyer [12517]
The cubic equation formed is L^3 - 52L +144 = 0. Dimensions: Length = 4 inches, Width = 2 inches, Height = 3 inches. To determine this, let L be the length, W the width, and H the height. The box volume is 24 cubic inches, and its total surface area is 52 sq. inches. Setting W = L/2 leads to Volume = L * W * H, thus substituting W gives us the equation 0.5L^2 * H = 24 resulting in H = 48/L^2. The surface area equation simplifies to (L*W) + (L+H) + (W+H) = 26. Introducing W = 0.5L yields 0.5L^2 + 1.5LH = 26. Substituting H into this gives 0.5L^2 + 72/L = 26. Multiplying throughout by L to eliminate denominators yields 0.5L^3 - 26L + 72 = 0. After multiplying through by 2: L^3 - 52L +144 = 0. Testing L=4 confirms a factor, thus Length (L) = 4 inches, and subsequently, W and H calculate to 2 inches and 3 inches respectively.
4 0
2 months ago
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