Having no profit indicates that P(x)=0: x³-4x²+3x-12=0
factor this by regrouping: x²(x-4)+3(x-4)=0
extract (x-4): (x-4)(x²+3)=0
thus, x=4 or x²=-3
since x² cannot be negative, the only viable solution is x=4.
Answer:
D.
Step-by-step explanation:
This function is piece-wise, meaning you will have two equations along with distinct domains. The equation x squared plus 3 illustrates a parabolic curve, while x plus 4 is depicted as a linear function. There is a specific reason why the point on the parabola is open at x equals 4; this signifies that the value does not satisfy the equation. Therefore, x cannot equal 4 for the parabola, so its domain is x less than 4. The closed point on the linear function indicates that when x is 4, it is part of the solution for that equation and graph. Consequently, the domain for the linear function is x greater than or equal to 4. Hope this clarifies things!
Answer:
160/1001, 175/1001
Step-by-step explanation:
i) We calculate:
₈C₁ methods to select 1 new camera from a selection of 8
₆C₃ methods to select 3 refurbished cameras from a selection of 8
₁₄C₄ methods to select 4 cameras from the total of 14 cameras
The probability formula is:
P = ₈C₁ ₆C₃ / ₁₄C₄
P = 8×20 / 1001
P = 160 / 1001
P ≈ 0.160
ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:
P = ₆C₄ / ₁₄C₄
P = 15 / 1001
Therefore, the combined probability is:
P = 160/1001 + 15/1001
P = 175/1001
P ≈ 0.175
The third option is correct. Step-by-step explanation: Various transformations apply to a function f(x). If a transformation is applied downward by 'k' units, the function shifts down; if upward, it rises 'k' units. Additionally, if scaled vertically by a factor of 'b', it will stretch; if reflected over the x-axis, the operation is indicated. Thus, since the parent function has undergone reflection over the x-axis, a vertical stretch by a factor of 2, and a downward shift of three units, we can derive that the transformed function is presented.
