All categories

2 months ago

A piece of metal has a mass of 2210 g. The volume of the metal is 260 cm³.

Mathematics

2 answers:

Leona [12.6K]2 months ago

7 0

Answer:

$8.5g*cm^{-3}$

Step-by-step explanation:

The calculation for density is mass divided by volume.

$\rho=\frac{m}{V}$

$\rho =\frac{2210}{260} =8.5g*cm^{-3}$

Svet_ta [12.7K]2 months ago

6 0

Answer:

$density= 8.5\,\,\frac{g}{cm^3}$

Step-by-step explanation:

Recall the density formula:

$density=\frac{mass}{volume}$

Applying this to the current situation gives us:

$density=\frac{mass}{volume} \\density=\frac{2210}{260} \,\frac{g}{cm^3} \\density= 8.5\,\,\frac{g}{cm^3}$

You might be interested in

A man 50 years old has 8 sons born of equal intervals. The sum of the ages of the father and sons is 186. What is the age of the

babunello [11817]

<span>Denote x as the interval, then: 186 = 50 + 3 + (3+x) + (3+2x) + (3+3x) + (3+4x) + (3+5x) + (3+6x) + (3+7x) 186 = 74 + 28x x = 4 Age of the eldest son = 3+7x = 3+28 = 31.</span>

8 0

1 month ago

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red

Zina [12379]

There are several possible outcomes. The initial composition of the urns is as follows: Urn 1 contains 2 red chips and 4 white chips, totaling 6 chips, whereas Urn 2 has 3 red and 1 white, amounting to 4 chips. When a chip is drawn from the first urn, the probabilities are as follows: for a red chip, it is probability is (2 red from 6 chips = 2/6 = 1/2); for a white chip, it is (4 white from 6 chips = 4/6 = 2/3). After the chip is transferred to the second urn, two scenarios can arise: if the chip drawn from the first urn is white, then Urn 2 will contain 3 red and 2 white chips, making a total of 5 chips, creating a 40% chance for drawing a white chip. Conversely, if a red chip is drawn first, Urn 2 will contain 4 red and 1 white chip, which results in a 20% chance of drawing a white chip. This scenario exemplifies a dependent event, as the outcome hinges on the type of chip drawn first from Urn 1. For the first scenario, the combined probability is (the probability of drawing a white chip from Urn 1) multiplied by (the probability of drawing a white chip from Urn 2), equaling 26.66%. For the second scenario, the probabilities yield a value of 6%.

8 0

1 month ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

Inessa [12570]

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format $y/x=k$ or $y=kx$

For this question, we have

the point $(5,12)$ lies on the direct variation line

therefore

Determine the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

The equation is

$y=\frac{12}{5}x$

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point $(0,0)$

$x=0\ y=0$

Insert the values of x and y into the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is valid

thus

the point $(0,0)$ lies on the direct variation line

case B) point $(2.5,6)$

$x=2.5\ y=6$

Insert the values of x and y into the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is valid

thus

the point $(2.5,6)$ lies on the direct variation line

case C) point $(3,10)$

$x=3\ y=10$

Insert the values of x and y into the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not valid

thus

the point $(3,10)$ does not lie on the direct variation line

case D) point $(7.5,18)$

$x=7.5\ y=18$

Insert the values of x and y into the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is valid

thus

the point $(7.5,18)$ lies on the direct variation line

case E) point $(12.5,24)$

$x=12.5\ y=24$

Insert the values of x and y into the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not valid

thus

the point $(12.5,24)$ does not lie on the direct variation line

case F) point $(15,36)$

$x=15\ y=36$

Insert the values of x and y into the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is valid

thus

the point $(15,36)$ lies on the direct variation line

ultimately

the solution is

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

1 month ago

Read 2 more answers

Ax+16=b−3x what is a= and what does b= ?

PIT_PIT [12445]

Response:

Slope=4

x−intercept=−

=−4

b−intercept=

=16.0000

Detailed breakdown:

7 0

1 month ago

Which number line represents the solutions to |–2x| = 4? A number line from negative 10 to 10 in increments of 2. Two points, on

Zina [12379]

Answer:

Two solutions exist, specifically one at -2 and another at 2.

Step-by-step explanation:

|–2x| = 4

2x = 4 leads to x = 2 and

2x = -4 leads to x = -2.

9 0

1 month ago

Read 2 more answers