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Lera25
9 days ago
13

Shareen performs a skit to model a method of charging. In the skit, a painter shakes her hand and gets paint on her.

Physics
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Six pendulums of mass m and length L as shown are released from rest at the same angle (theta) from vertical. Rank the pendulums
Sav [3153]

Answer:   1m, 1m, 2m, 2m, 4m, 4m.

It’s important to remember that the masses attached do not influence the number of oscillations.

Explanation:

To determine the number of oscillations (complete cycles), we can apply the formula n = t / T ……equation 1

The variables that impact the period of a simple pendulum are solely its length and gravitational acceleration. The period remains unaffected by factors such as mass.

period (T)= 2 x π x √(L/g) ….equation 2

where π = 3.142, L= rope length, and g = 9.8 m/s (gravitational acceleration)

According to the question, the time (t) is 60 seconds.

By merging equations 1 and 2, we obtain  

number of oscillations = time / (2 x π x √(L/g))

Case 1: for L = 4m

number of oscillations = 60 / ( 2 x 3.142 x √(4/9.8))

= 14.9 = 14 complete cycles (the problem specifies complete cycles)

Case 2: for L = 2m

number of oscillations = 60 / ( 2 x 3.142 x √(2/9.8))

= 21.4 = 21 complete cycles

Case 3: where L = 4m, results in the same as case 1, yielding 14 complete cycles

Case 4: where L = 2m, mirrors the outcome in case 2, producing 21 complete cycles

Case 5: in the instance of L = 1m

number of oscillations = 60 / ( 2 x 3.142 x √(1/9.8))

= 30.1 = 30 complete cycles

Case 6: when L = 1m, which repeats case 5, also gives 30 complete cycles

From these findings, the order of the pendulums from the highest to lowest number of complete cycles is as follows: 1m, 2m, 2m, 4m, 4m.

Remember, the number of oscillations is independent of their respective masses.

3 0
3 months ago
Read 2 more answers
A robot probe drops a camera off the rim of a 239 m high cliff on mars, where the free-fall acceleration is −3.7 m/s2 .
Maru [3345]
<span>a. To determine the velocity at which the camera strikes the ground: v^2 = (v0)^2 + 2ay = 0 + 2ay v = sqrt{ 2ay } v = sqrt{ (2)(3.7 m/s^2)(239 m) } v = 42 m/s The camera impacts the ground with a speed of 42 m/s. b. To calculate the duration it takes for the camera to reach the bottom: y = (1/2) a t^2 t^2 = 2y / a t = sqrt{ 2y / a } t = sqrt{ (2)(239 m) / 3.7 m/s^2 } t = 11.4 seconds
       
The camera descends for 11.4 seconds before hitting the ground.</span>
3 0
2 months ago
James Cameron piloted a submersible craft to the bottom of the Challenger Deep, the deepest point on the ocean's floor, 11,000 m
serg [3582]

Answer:

4.1\cdot 10^8 N

Explanation:

To begin with, we must determine the pressure acting on the sphere, which is calculated using:

p=p_0 + \rho g h

where

p_0 =1.01\cdot 10^5 Pa denotes the atmospheric pressure

\rho = 1000 kg/m^3 represents the density of the water

g=9.8 m/s^2 signifies the acceleration due to gravity

h=11,000 m indicates the depth

By substituting these values,

p=1.01\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(11,000 m)=1.08\cdot 10^8 Pa

The sphere's radius is calculated as r = d/2 = 1.1 m/2 = 0.55 m

Thus, the sphere's total surface area can be expressed as

A=4 \pi r^2 = 4 \pi (0.55 m)^2=3.8 m^2

Consequently, the inward force acting on the sphere equals

F=pA=(1.08\cdot 10^8 Pa)(3.8 m^2)=4.1\cdot 10^8 N

8 0
2 months ago
Read 2 more answers
Calculate the critical angle between glass (n = 1.90) and ice (n = 1.31)? 43° 52° 60° 75°
Maru [3345]
According to Snell’s Law: Where: is the index of refraction of the first medium (glass), and is the index of refraction of the second medium (ice). The angle of incidence and the angle of refraction are represented by and. The refractive index quantifies the speed of light in a medium. The critical angle is identified as the angle at which total internal reflection occurs, meaning no light passes through into another medium. This phenomenon happens only when the light is transitioning from a medium with a higher index of refraction to one with a lower index of refraction.
4 0
2 months ago
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