Answer:
The exponential equation can be expressed as A = 600(1.04)^15
After 15 years, the value of the mutual fund will be $1,081
Step-by-step explanation:
The worth of the mutual fund after a specific number of years can be represented by the compound interest formula shown below;
A = P(1 + r/n)^nt
In this formula, A stands for the mutual fund's value after 15 years, P represents the principal amount invested, which is $600, r denotes the interest rate at 4% or 0.04 (thus, 4% = 4/100 = 0.04), n indicates the number of times compounding occurs per year (in this case, it is done once a year), and t represents the number of years, which is 15.
Now, substituting in these values gives us;
A = 600(1 + 0.04/1)^15
A = 600(1.04)^15
A = $1,081 approximately
d Step-by-step explanation: when f(x)=5......It can also be expressed as f(x)=1/125(625x). This is applicable to any whole number over one, with 1(625x)=625x. Therefore, since 125(1)=125, we find (625/125)x=5x.
Only amend the first item. Please refer to the graph in the attached file. 1) a rectangle with A(3,3), B(3,6), C(7,6), D(7,3) having adjacent sides (in green) 2) a parallelogram with A(2,0), B(3,2) having nonperpendicular sides (in blue) C(6,3), D(5,1) 3) a square with A(3,3), B(2,5), C(4,6), D(5,4) (in red) 4) a rhombus with A(2,-2), B(3,0), C(4,-2), D(3,-4) having adjacent sides (in black)
The function can be expressed as:
f(x) = log(-20x + 12√x)
To ascertain the maximum value, differentiate the equation with respect to x and set the derivative to zero. The procedure unfolds as follows.
The differentiation formula is:
d(log u)/dx = du/u ln(10)
Thus,
d/dx = (-20 + 6/√x)/(-20x + 12√x)(ln 10) = 0
-20 + 6/√x = 0
6/√x = 20
From which we derive x = (6/20)² = 9/100
Therefore,
f(x) = log(-20(9/100)+ 12√(9/100)) = 0.2553
The function's maximum value is 0.2553.
