a) P(identified as explosive) equals P(actual explosive & identified as explosive) + P(not explosive & identified as explosive) = (10/(4*10^6))*0.95+(1-10/(4*10^6))*0.005 = 0.005002363. Thus, the probability that it actually contains explosives given that it's identified as containing explosives is (10/(4*10^6))*0.95/0.005002363 = 0.000475. b) Let the probability of correctly identifying a bag without explosives be a. Therefore, a = 0.99999763, approximately 99.999763%. c) No, even if this becomes 1, the true proportion of explosives will always be below half of the total detected.
Step-by-step explanation:
The difference quotient represents the slope of the line connecting two points on a curve. To achieve the most accurate estimate, we need to use points that are nearest to x = 0. For this problem, the relevant points are (-0.001, 1.999) and (0.001, 2.001).
m = (2.001 − 1.999) / (0.001 − (-0.001))
m = 1
Total Cost, C = $(16S + 56). Step-by-step explanation: Chris purchases 8 more Ninja Turtles than Star Wars action figures. The cost per Ninja Turtle is $7, while each Star Wars figure costs $9. If we let S represent the number of Star Wars figures bought, then the number of Ninja Turtles becomes S + 8. The cost for S Star Wars figures is $9S. Similarly, for (S + 8) Ninja Turtles, the total cost is $(7S + 56). Therefore, the overall Total Cost is represented by the sum of the costs for both types of figures, leading to the Total Cost being expressed as C = 9S + (7S + 56).
